I print F, I backslash N, just to pretty up the screen, ArgC I then iterate from, I equal zero up to Arg C; so Arg C is the convention.
我键入printf,反斜杠n,来使屏幕变得美观点,然后i开始迭代,从i等于0增加到;,所以ArgC是一个约定。
So when we count, generally, again, we start from zero, we go to N minus 1.
当我们计数时,一般的,再次强调,我们从0开始,到N-1结束。
e The charge on the anion times minus e, so there is the minus e squared, 0R0 and divided by 4 pi epsilon zero r naught, because now I am evaluating this function at r naught, one minus one over n where n is the Born exponent.
阴离子的电荷乘以,因此会有-e的频繁,除以4πε,因为现在我用r圈评估这个函数,1-1/n,n是波恩指数。
If n is greater than zero, I decided I would say, "You picked a positive number, backslash n," so put the cursor on the next line, else if n was not less than zero, I say, "You picked a negative number, backslash n."
如果n比0大,我就决定来说:,“你选择了一个整数,反斜杠n“,所以你把光标,放在下一行,另外如果n不小于0,我说:,“你选择一个负数,反斜杠n“
This is E equals zero. N equals infinity.
这是第N个能级,能量为。
It's gonna be zero if N is less than 2, right.
如果N小于2,T应该是。
Right. N is over here for counting from zero.
对的,从0开始计数,N到了这边。
Well, this question mark becomes an O, this question mark becomes an O, and then the loop terminates 0 1 2 because it's iterating from zero to N so that's zero, 1, 2 and the length of the string is 3 so the loop terminates, but I remember that I needed to have this special sentinel value so I'm just going to put it there manually.
嗯,这个问号变成了,这个问号变成了0,然后循环结束了,以为迭代从0到N,那就是,字符串的长度是3,然后循环就结束了,但是我记得我需要这个特殊的标记值,所以需要手动的加上它。
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