• Musical performers also included Madonna,Jay-Z,Rihanna, Bono and the Edge.

    VOA: special.2010.02.01

  • So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.

    这里不再等于-z的平方,现在我们等于-有效的z的平方,乘以RH除以n的平方。

    麻省理工公开课 - 化学原理课程节选

  • So z equals 7 -- this is the cut-off where, in fact, the sigma orbital is going to be higher in energy than the pi 2 p orbitals.

    所以z等于7-这是分界点,实际上,sigma轨道能量,要比π2p轨道高。

    麻省理工公开课 - 化学原理课程节选

  • Let's bind z eh let's bind z to the-- f if I could type it would help-- say, f of 3. OK?

    让我们给z赋值--如果我能打字就好了-,比方说?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • It looks a little something like that, and the screen doesn't quite do it justice here, Z but there's two alphabets; A through Z, and then A through Z, -- but the inner A through Z is on a small -- it has a smaller diameter; so it's a ring of letters.

    它看起就像那样的东西,那个画面做的不是这么公正,这里有两个字母表,A到Z,然后A到,但是戒指内部的A到Z是在一个小直径的上面-,它有一个小的直径,所以它是一个有字母的戒指。

    哈佛公开课 - 计算机科学课程节选

  • We have two of them on the z-axis like this.

    他们俩的z轴都这样。

    麻省理工公开课 - 固态化学导论课程节选

  • I know they have a lot of... Jay-Z, the rap star, he was there.

    我知道他们有很多的……Jay-Z,饶舌歌星,他就在那儿。

    麦迪逊广场花园 - SpeakingMax英语口语达人

  • Peter's new fleet, we'll talk about his new fleet, which he oversaw and, in a very minor way, helped build himself, sails down the Don River in 1698 and takes the Turkish port of Azov, A-Z-O-V, on the Sea of Azov.

    我们接下来讲讲彼得的新舰队,尽管影响不大,但他亲自监督,并且参与组建了这个舰队,舰队于1698年沿顿河顺流而下,直取土耳其的亚速港,在亚速海上

    耶鲁公开课 - 欧洲文明课程节选

  • That's it. Again, these other p dxy dyz - or the d x y, d y z, those are going to be those more complicated linear combinations, you don't need to worry about them.

    同样,这些p轨道,或者,它们是一些,很复杂的线性组合,你们,不用管它。

    麻省理工公开课 - 化学原理课程节选

  • So what we can say is look at each of these separately, so if we start with looking at the 2 p z orbital, the highest probability of finding an electron in the 2 p z orbital, is going to be along this z-axis.

    我们可以来分别看看这些图,首先来看看2pz轨道,在2pz轨道里,找到电子的最大概率,是沿着z轴。

    麻省理工公开课 - 化学原理课程节选

  • And the reason is simply because the energy that Z we gain in terms of moving up in z, 5 so from going to z equals 4 to z equals 5, -- is actually outweighed by the energy it takes to go into this new shell, to go into this new sub shell.

    原因很简单,就是因为我们通过提升,所得到的能量--从,Z,等于,4,到,Z,等于,事实上比填充到这个新的壳层,新的亚壳层,所消耗的能量更多。

    麻省理工公开课 - 化学原理课程节选

  • Um-hmm. So, it's going to be the y z nodal plane, or in other words, we can say it's any place where phi is equal to 90 degrees.

    嗯,是yz平面,换句话说,是在phi等于90度的面。

    麻省理工公开课 - 化学原理课程节选

  • So, essentially when we're talking about these equations up here, all we're doing is talking about the regular Rydberg formulas, but instead we could go back and re-derive the equation for any one electron atom, which would just mean that we put that z squared term in the front.

    所以本质上,当我们讨论,这些问题时,我们说的是常规的,Rydberg公式,但对任何其他单电子原子,我们不用,从头再推到,而是仅仅把,z平方项放在前面。

    麻省理工公开课 - 化学原理课程节选

  • These are both z-axis.

    他们俩都是z轴。

    麻省理工公开课 - 固态化学导论课程节选

  • Specifically, it's always the z that forms the sigma orbital, and the reason is at least at a minimum for this class we always define the internuclear axis as the z axis, so this is always the z axis, so it's always going to be the 2 p z's that are coming together head-on.

    特别的,z总是形成sigma轨道,这是因为至少在这个课里面,我们总是定义核间轴为z轴,所以这总是z轴,所以2pz轨道总是,朝一个方向出现。

    麻省理工公开课 - 化学原理课程节选

  • And the convention is that when two atoms bond, they bond along the z-axis.

    我们的惯例是,两个轨道成键,键轴为Z轴。

    麻省理工公开课 - 固态化学导论课程节选

  • z And what you need to remember is if the z 8 is equal to eight or greater, such as oxygen being the cut-off point, this sigma 2 p orbital is actually lower in energy than the pi 2 p orbitals, the molecular orbitals.

    你们要记住如果,等于或者大于,就像O是分界点,这时sigma2p轨道,比π2p轨道能量更低。

    麻省理工公开课 - 化学原理课程节选

  • This is Pieter Claesz, C-L-A-E-S-Z, probably mispronounced.

    这是彼得·格莱兹的作品,C-L-A-E-S-Z,我可能发音不准确

    耶鲁公开课 - 欧洲文明课程节选

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