int *x So I have int *x.

所以我用。

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Y Why don't I say int temp gets X. Let's say Y oh, sorry, X gets Y and then Y gets temp, this 2 would fail.

为什么我不说明，int，temp，=，X，让我们说明,哦，对不起，X=Y，然后，Y=temp，这两行将失败的。

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y A square it's called X, another square it's called y and now this time I'm doing pointers to int not points to char.

一个叫做x，另外一个叫做,这一次是int型指针,不是char型指针。

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int X Well, if you declare int X up top, you could certainly update X to one here.

嗯，如果你在顶端声明，你可能把X更新为1了。

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So this line here declares a variable, just storage space called "x" and it's of type "int," which means an integer has to go in it.

这里的这条线声明了一个变量，一个叫做“x“的存储空间，它的类型是“int“,意思是里面存储的是整数型的数据。

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malloc I'm going to now use this new, fancy function called malloc and I'm going to say x gets the return value of malloc of the size of an int.

我现在使用这个新的，别致的函数,然后我指明x，=，malloc的int型数据的大小,的返回值。

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And actually, if I don't want to clobber, as we say, overwrite the value of my variable, ; I could declare another one and store the return value in Y; Y so now I have two ints in memory; X and Y, 3 one with two, one with three.

实际上，如果你不想彻底清除，像我们说的，覆盖那个变量的值，我可以申明另一个变量Y，并在Y中保存那个返回值;,现在内存中有两个int数，X和，一个的值为2，一个为。

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I'm going to call it x and how do I make a pointer to an int?

我把它叫做x，我怎样声明一个int型指针？

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int Y Well, I said int X and int Y; so that gave me one square here called X, one square here ; or wherever, called Y, done, one was put in here; two was put in here, and then I called this function swap.

好的，我声明了int，X，和;,然后我这里有个正方形叫做X，一个正方形,叫做Y，完成，1放在这里;,2放在这里，然后我调用这个swap函数。

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