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It's not like all the orthopedic injuries I've had where you go get an MRI or an X-ray and you get it fixed.
VOA: standard.2010.02.26
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Right. So X get assigned the value of Y, but then Y gets the value of X; so what have you really done?
对的，X被赋值成Y的值了，然后Y获得了X的值，你到底做了什么呢？
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Let's test it in all possible combinations of x and y and see if we get the right answer.
来测试并看看,返回的结果正确不正确。
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So you're clobbering the value of X and then you can't get back X's value because it's too late.
所以你们清除了X的值,然后你们不能找回X的值了，因为太晚了。
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For example, if you started here and you did all this and you came back here, the average velocity would be zero, because you start and end at the same value of x, you get something; 0 divided by time will still be 0.
例如,如果你从这里开始运动,经过这个过程又回到这里,平均速度就是0,因为初态和末态的位移相同,你得到了什么呢,0除以时间还是0
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There is no way that you could irradiate a crystal of nickel with a single beam of x-rays and get that circular ring pattern if the electron beam were behaving as a particle beam only.
没有什么其他的途径,可以让镍晶体发射,单束X光来,继而得到环状图案,如果电子束,是以粒子束形式出现的。
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That's a choice, and that choice turns out to be very interesting and really important, because if you connect these two points together, you get a straight line that has to intercept the x-axis at some point.
在这一选择下,我们会发现一件非常有趣，而且极其重要的事,当你把这两点用直线连接起来，你会发现这条直线,将与x轴在某点相交。
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How would we go about, I mean I don't want to do it because I'll probably get it wrong, but if I wanted to solve out for this X and the Y, since this is a QR class, let's just talk about it a second.
我们怎么解呢,我的意思是我现在不会去计算,因为我可能会算错,但是如果你真的很想解出X和Y的值,介于这是一节需要快速反应的课,那我们花些时间来探讨一下吧
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This is saying, that's a class, true or sorry, an instance of a class, and I'm going to get the x value associated with it.
那么两个点是同一个点，我会返回，注意格式，这儿的意思是,它是一个类，噢对不起。
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Otherwise, I'm going to get a new guess by taking g, x over g, adding them, 2 and dividing by two.
或者呢，我会有一个关于g的新猜想,就是X大于g，将二者相加，然后除以。
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And obviously, when I get to something whose square is equal to x, I've got the answer I want, and I kick it out.
大于x的时候，我已经经过了,想要的答案了，很明显,当我得到一个数的平方等于x的时候。
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And keep going, until the square of one of those integers is greater than or equal to - sorry, just greater than x. OK, why am I doing that? When I get greater than x, I've gone past the place where I want to be.
如果还是比x小的话，跳到3，这么继续下去,直到一个整数的平方大于或者等于,对不起，是大于x，好,为什么我要这么做呢？,让我得到的整数的平方和。
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We've seen in class that you get garbage values if you don't initialize something to a value so let me actually initialize x to a value.
我们在课程上了解到，如果你不给一个变量,进行赋值，它会获得一个无效值,让我把x初始化为一个值。
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If de Broglie is correct, let's irradiate the nickel crystal with a beam of electrons where the wavelength of the beam of electrons is identical to the wavelength of the x-rays that were used and see what we get.
如果德·布罗意是正确的，那么镍晶体放出,电子光束,电子束的波长,和原来讲过的X光的波长是相等的,再看看得到了什么。
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We know it's going around in a circle because if I find the length of this vector, which is the x-square part, plus the y-square part, I just get r square at all times, because sine square plus cosine square is one.
我们之所以知道它做圆周运动,是因为我求出了这个矢量的模长,也就是 x 的平方加上 y 的平方,我就得到了它在任意时刻的模长平方,因为正弦平方加余弦平方始终等于1
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That statement says, get the value of x, which is this link, and give z a pointer to the same place.
这个声明的意思是，取得x的值，也就是连接指向的值，然后给z赋予一个指向同样位置的指针。
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And then from that start point, get the x-value. Same thing, from that instance, get the endpoint, from that end point get the x-value, square.
取得结束点，然后取得结束点的y坐标，然后求差开平方，然后同样求的y坐标。
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I going to come back in a second to how it actually does that, but it basically says, get me x value for p 1, get me the x value for p 2, compare them, just as you would normally.
是一个类的实例,我要去取的这个实例，所关联的x值，我稍后会讲讲实际上，这里是怎么实现的，但是基本上它的意思就是，给我p1的x值。
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x and get the values of x and y attached to this thing and return them to me.
和y值然后把它们返回给我，It’s，going，to，go，off,这就是我想要的东西,我想要我的类里面有一些方法。
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Locally x got bound to 3, 3 I added 1 to it, whoop-dee-doo, 4 I get back a 4. But what's the value of x?
这是我想要的对吧？,在局部程序中x被赋值为，我给它加了1，我得到了？
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If you want to add two vectors, you can add the arrows by the rule I gave you or just add the components of x of the two guys to get the component of the sum and likewise for the y.
如果要把两个矢量相加,你可以用我教给你们的箭头相接的方法,或者就将二者的 x 分量相加,得到和矢量的 x 分量,y 方向也是这样
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