With Vicksburg in Union hands, the North could control the whole length of the river.
VOA: special.2009.11.19
That's the vector parallel to i, with length Bx.
这个是平行于 i,模长为 Bx 的矢量
Still quadratic, right? I'm looking for the worst case behavior, it's still quadratic, it's quadratic in the length of the list, so I'm sort of stuck with that.
还是平方,对吧,我在寻找最坏的情况,它还是平方,它是列表长度的平方,我对此有点无奈了。
It describes a rectangle with a length about one and one-half times its width.
VOA: special.2010.06.06
And, I know I need to come up with four symmetric equi-length bonds, and let's just see, let's draw the structure here.
我想我们需要,4个对称的等长的键,让我们画出CH4的结构。
That's an excellent question, especially looking into factors that affect the return-generating process in the stock market-in other words, factors that affect the stock prices in a conventional sense: Market liquidity, length of the daily fasting period, especially contrasting summer months with winter months when Ramadan coincides with one versus the other, with the length of day being really longer during summer months.
VOA: standard.2010.08.05
Even though there's four bytes the length of the string is consistent with what a human being would interpret as the length 3 of the string which is 3.
即使那里有4个字节,字符串的长度,与我们所认为的长度是一致的,字符串的长度是。
I'd be happy to discuss with you, outside class, at greater length my favorite theories as to where the argument goes wrong and why I think it goes wrong in Descartes' case as well.
就笛卡尔的论证到底错在哪儿的问题,我很愿意在课外,和你们详细谈谈,我最信服的理论,以及我个人的看法
But then, I combine i times Ax with i times Bx, because that's the vector parallel to i, with the length Ax.
然后我把 i ? Ax 和 i ? Bx 加起来,因为这是平行于 i,模长为 Ax 的矢量
Because if you did what I suggested with the list, the time to look up the key would be linear in the length of the list. You'd have to look at each element until you found the key.
字典是用一种很神奇的,叫做散列法的算法,来实现的,后面我们将,会学到一点关于。
I think it depends on whether the list is odd or even in length. Actually, that's probably not true. With one, it'll probably always get it down there, but if I've made it just equal to two I might have lost.
是奇数还是偶数,事实上,这是不正确的,如果最后剩下一个,那可能得到了结果,如果剩下两个,可能错了,所以,首先我们要格外。
And now you have a tetrahedron with equal length bonds.
四面体型的四根等长的键。
So if I start off with a list of length n, how many times can I divide it by 2, until I get to something no more than two left?
我能够除以多少次2呢?,直到我得到的长度不超过2么?,对数次,对吧?就像刚才那位同学说的那样?
You're going to get a chance to explore them, and you'll see not only are there the standard numerics for strings, there are things like length or plus or other things you can do with them.
以后你们还会学到更多,你会学到字符串,不仅仅能运用标准数值运算,你还可以对他们求长度,或者加上其他的东西。
It's not true, by the way, of all programming languages. In fact, Professor Guttag already talked about that, in some languages lists take a time linear with the length to get to it.
顺便说一句这在大部分,编程语言中做不到,实际上Guttag教授已经说过这一点了,在一些语言中取得数组,要花费时间是线性长度的。
I just doubled the indentation each time so you can see it. So each successive call, notice what's happening. The argument is getting reduced. And we're going another level in. When we get down to this point, we're calling it with just a string of length one.
因此每次成功调用注意它的过程,我们的命题不断简化,而且我们不断深入嵌套,当我们走到这一步的时候,我们就是在调用它处理,仅有一个元素的字符串了。
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