-
And, in fact, since we're going to reuse this again and again during today's lecture, I'm going to put it over here and leave it sacrosanct for our further use.
实际上，因为我要,一遍又一遍的用到这个公式，我会把它放在这里,以强调其会被不断使用的神圣地位。
-
You're going to see the arguments about space if you take some of the courses that follow on, and again, some nice courses about that. For this course, we're not going to worry about space that much. What we're really going to focus on is time.
在以后的其他课程上你们,会学到一些关于空间的参数,一些讲这个的,很不错的课程，但是在这门课上,我们并不太关心空间问题,我们真正关心的是时间问题。
-
- So again, if you're unwinding what's going on here, this-- we sorted the left half which meant sort the left half, then the right half then the merge.
同样，如果你展开正在进行的一切-,我们已对左半部分排好了序，接着右半部分，接着合并。
-
And in either case if we first talk about constructive interference, what again we're going to see is that where these two orbitals come together, we're going to see increased wave function in that area, so we saw constructive interference.
在任何情况下,如果我们首先讨论相长干涉的话，我们同样会看到,当这两个轨道靠拢的时候，我们看到这个区域有波函数增加，所以我们看到的是相长干涉。
-
Again, don't worry too much about the equation, we're not really going to do any math here, I'm just putting it in for completeness.
对这个方程也不需要太深究,在这里我们不强调数学运算的,我把它写出来是为了表述完整
-
All we're going to do here is really just, once again, scratch the surface.
我们在这里只是，肤浅地解析一下。
-
Because of the very loud wrong person we're going to try that again.
因为有一个人喊得特别大声,我们再来试一次。
-
So we're going to listen now to the end of Strauss's Death and Transfiguration, and again we've got the idea of the octave, then the fifth, then the fourth.
我们下面会,听施特劳斯的死亡与净化直至结束,我们再次了解了八度音阶,然后是第五音阶,第四音阶
-
We want to have that definition clear because in fact we're going to, we might want tabulate heats of reaction, right, and of course want to know what the conditions are for the tabulated values apply. And we're going to want to calculate them from other quantities and again, we're going to need to know each case what are the relevant conditions?
我们想要明确这个定义,因为实际上我们会想把,反应热制成表格，当然我们会,想知道表中的数据在什么样的,条件下是有效的，我们会,想要从其他的量中算出它们,再一次，我们需要知道,每种情形下相关的条件是什么？
-
The only other thing--then next period we're going to talk-- on Friday we're meeting again and we're meeting again about-- this time it's about efficient markets and I want to talk about the evidence for efficient markets and against it and that will lead you into your third problem set about efficient markets.
下节课的主题是,我们将在周五的课上讨论,有效市场问题,我要讨论关于支持和反对,有效市场的证据,那时你们可以开始做,第三本习题集,是关于有效市场的
-
Things like addition and multiplication, which we saw not only apply to numbers, but we can use them on things like strings and we're going to come back to them again.
就像加法和乘法，我们已经学习过，它们不仅仅可以应用于数字，还可以用到字符串上,我们今天还会再讲讲。
-
Anybody, again this is a 115 kind of exercise, we're going to be moving lines around.
谁知道,这是经济学115的习题,我们要移动这些值线
-
And this again is what we're going to call a bonding orbital.
同样，我们叫它成键轨道。
-
Let's go the other direction. And yes, I guess I'd better say s not 2, or we're going to get an error here. Again, in twenty-three checks.
这里我得说不能是2，否则要报错了，再一次，调用了23次,在这个例子里，它从尾部开始。
-
But here we're going to add 1, so again, we have 10 valence electrons.
但是这里我们要加上一个，那么跟刚才一样，我们有十个价电子。
-
And when we talk about size, I'm again just going to say the stipulation we're not talking about an absolute classical concept here, but in general we're going to picture it being much further away from the nucleus as we move up in terms of n.
当我们说到尺寸时，我们只是说――,经典的绝对的概念，而是它大约,离原子核有多远。
-
This is a little file I created, all right, and I'm going to start with a sequence of these things and walk them along, again I invite you to put comments on that handout so that you can follow what we're going to do. All right?
这是我创建的一个小文件，好，然后我回去以一系列这样的事情,开始然后进行下去，我还是想大家都在手册上做一些注释,这样我们就能对将要做的事情,做一个记录了，对不对？
-
The crucial premise--Again, we're going to just grant Plato the metaphysics.
关键的前提是,我们依然直接承认柏拉图的形而上学
-
Again, we're going to take the linear combination of those p atomic orbitals and make what are called pi or some more sigma molecular orbitals.
同样的，我们需要得到,原子p轨道的线性组合,然后组成我们所说的,π分子轨道或者sigma分子轨道。
-
We're going to listen to it again.
我们再来听一遍
-
So let's imagine we're playing the game again, once again you're going to the movies, once again the first one didn't happen so you didn't for some reason it was cancelled that night because someone had a bad cold or something.
我们再来进行一次这个博弈,假设你们又要一起去看电影,由于种种原因,第一天晚上你们都没有看成,假装因为有一个人感冒了
-
So we're to assume we can get to any piece of data, any instruction in constant time, and the second assumption we're going to make is that the basic primitive steps take constant time, same amount of time to compute. Again, not completely true, but it's a good model, so arithmetic operations, comparisons, things of that sort, we're all going to assume are basically in that in that particular model.
因此如果我们假设在恒定的时间内,我们可以取得任何一块数据,任何一种数据结构的话,我们要做的第二个假设就是,基本的原始操作计算花费的时间是恒定的,这个假设也不是完全正确的，但这个模型其实挺不错的，因此算法操作，比较，这一类的事情，我们在这个特定的模型中都假设是基本的,操作，花费的时间是恒定相同的。
-
PROFESSOR: Two. OK, good. So again, we're going to see that we have a bonding order of 0.
两个，OK，很好，同样的，我们会看到键序是0。
-
And what we're actually talking about again is the zeffective. So that z effective felt by the 2 p is going to be less than the z effective felt by the 2 s.
我们实际上所谈论的,所以被2p感觉到的,的有效电荷量,有效电荷量小于2s感觉到。
-
All right, so if we think about b h bond here, again, it's the sigma bond, and we're going to say it's a boron 2 s p 2 hybrid orbital interacting with a hydrogen 1 s orbital.
这可以告诉我们，为什么它倾向于周围只有6个电子，好了，考虑一下这里的BH键,同样的，它是sigma键,我们说。
-
So carbon has four valence electrons, so if we talk about c 2, again we're going to start filling in our molecular orbitals, and now we're going to have eight electrons to fill into our molecular orbitals.
碳有4个价电子，所以如果我们考虑C2的话，同样，我们开始填分子轨道，现在我们有8个电子,要填入分子轨道。
-
So again, we can name these molecular orbitals and these we're going to call also to point out there is now a bond axis along this nodal plane, which is something we didn't see before when we were combining the s orbitals.
同样的，我们可以,命名这些分子轨道,这些轨道叫做-同样要指出的是,现在沿着键轴是一个节点面，这是我们讨论s轨道的时候,从没有看到过的。
-
So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.
我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来，我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。
应用推荐