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Let's have a little review of the career of the great poet Orpheus as we get it certainly in L'Allegro and Il Penseroso.
让我们看看伟大诗人俄耳甫斯的经历,这在《快乐的人》和《沉思的人》中都有所提及。
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Let's test it in all possible combinations of x and y and see if we get the right answer.
来测试并看看,返回的结果正确不正确。
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If de Broglie is correct, we could then model the electron in its orbit not moving as a particle, but let's model it as a wave.
如果德布罗意是对的，那么我们可以在电子轨道中建立电子模型,不是像粒子一样运动，而是像波一样运动。
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Instead if we want this pointer to represent the address of something in as much as it points at that address let's just draw an arrow.
如果我们想要让这个指针表示,数据的地址，它指向的地址,我用一个箭头表示。
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Let's see if we could sing it together because we're going to do this in a different way in a second.
那我们试试把它唱出来吧，一会我们就要换一种方法了。
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Let's re-draw this, so it looks a little bit neater, where we have a triple bond in the middle instead, and again, we need our negative 1 charge there.
让我们重写这个，这样看起来更整洁一点，我们有一个三键在中间，同样地，我们这里需要一个负电荷。
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Let me add, let me make it 17 people so we have an odd number, so go and sit in that row.
我再加一个人这样就是奇数17个人,请到那行中
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Now, a foreword is of course supposed to suggest how you should read the text that's coming. And so, if we take it on in that role, let's see what we see.
现在，一个序言当然是要建议大家,去读一下那本书，还有，如果我们借鉴这个作用，让我们看一下这个。
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Is this not the very thing we told you in Egypt, saying let us be we will serve the Egyptians, for it's better for us to serve the Egyptians than to die in the wilderness.
这跟你在埃及答应我们的不同，你说过让我们,我们应该服侍埃及人,伺候他们总比死在荒野中好。
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I think that we are in a difficult situation but maybe let's not panic about it.
我认为我们正处于一个困难时期,但是也许我们不用为此而恐慌。
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Take a plasmid, cut it open, insert a gene that we want into the plasmid, and then put that plasmid in a host cell, and let the host replicate it.
取一个质粒,把它切开,把目标基因放进去,然后把这个质粒植入到宿主细胞,让宿主来进行复制
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We've played it three times, Let's try and figure out what the equilibria looked like in this game.
我们做了三次,我们试着解决,此博弈中的均衡是什么样子
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ReadFloat We'll look at it in a second. Let me sort of set the stage up for this -- suppose I want to input -- I'm sorry I want you as a user to input a floating point number.
名字叫,我们来看一会，我先来设置下情景-,假设我想输入，抱歉,我希望你们作为用户来输入一个浮点数。
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there that we want to highlight. In particular, -- notice-- let me highlight it for you, if I can find it with the wrong glasses on-- we've got these return commands.
这里还有一些我们要引起注意的变化，特别是注意这个，让我给你们强调一下-,看看我能不能戴着这副度数不对的眼镜。
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So let's fill it out in this way, 2p keeping in mind that we're going to fill sigma out the pi 2 p's before the sigma.
让我们这样填上去，记住我们先填π,轨道再填。
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In fact, let me uncomment it so we can look at it.
实际上，让我把这里去掉注释,以便于我们观看。
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Now, in fact, that's as far as we can get with dominance arguments in this particular game, but nevertheless, let's just stick with it a second.
目前为止,这些就是我们通过,此博弈得到的全部与优势有关信息了,然而,我们来再深究一下
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We'll come back and discuss it more in a second, but before I do, let me mention that the same model, exactly the same idea, has an application in Economics.
我们一会再深入导论这个问题,在此之前,我再来列举一个模型,是经济学里面一个完全类似的模型
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So the strategy choices, we're not going to do it in hours, let's just normalize and regard these choices as living in 0 to 4, and you can choose any number of hours between 0 and 4.
我们用小时数来表示策略吧,用0到4的数字来标记这些策略,你可以从0到4中任选工作的小时数
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So, in terms of finishing our Lewis structure, we're actually not done yet here, even though we have full octets, and we've used up all of our valence electrons, and the reason is because it's c n minus, so we need to make sure that that's reflected in our Lewis structure, so let's put it in brackets here, and put a minus 1.
那么，根据我们的路易斯结构的完成情况，我们实际上还没有全部完成，尽管我们有了填满的“八隅体“,而且用完了所有的价电子，原因就是因为这是一个负离子，我们需要确保我们的路易斯结构能反映出这一点，所以让我们给它加个括号，再加个负一。
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OK? And in fact, if you look at the code up here, and it's on your handout, the very first one, x 1, right here- if I could ask you to look at it-- is a piece of code to do it. And I'm less interested in the code than how we're going to analyze it, but let's look at it for a second.
实际上，如果你看看,你们课堂发的材料上面的代码，第一页上的，就是那-,大家请看看实现的这一部分代码,我不太关心,我们会怎么解释这个代码,首先让我们先看看。
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I could still do the linear case, which is order n or I could say, look, take the list, let's sort it and then search it. But in that case we said well to sort it was going to take n log n time, assuming I can do that.
我仍然可以做O的线性搜索,或者也可以以这个列表为例，我们先将其进行排序,然后再进行查找，但是在这种情况下,要花费n，log，n的时间去对其进行排序。
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Let's pause it there, and as we said last time, it operates in that fashion, and that beginning gives us a good opportunity to make a distinction between two types of melody, between this idea of a motive and a theme.
稍微停一下,就像我们上次所说的那样,它是这样,编排的,乐曲的开始乐段给了我们很好的范例,来区分两种旋律类型,区分动机和主题
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So what we're going to converge in on to, is the S1*, let's call it in this case, is equal to 1 plus B S2* and that S2* is equal to 1 plus B S1*.
交点的横坐标是S1,暂且这么叫吧,S1*=1+BS2*,而S2*=1+BS1
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