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q Work is zero. Delta u is w plus q, work plus heat. This is zero, this isn't.
功是零，△U是w加，功加上热量，这个是零。
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U OK, so let's look at delta u. Delta u is q plus w.
好的，让我们看看Δ
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And, this involves the reaction of titanium tetrachloride with magnesium to form magnesium chloride plus titanium And, this was invented in 1937 by W. J. Kroll.
四氯化钛和镁,反应生成氯化镁和钛,1937年W。J。克劳尔发明了这个方法。
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w And that has to equal q plus w, summed up for all the steps.
等于q加，对所有过程相加。
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u=q+w All right, what is delta u? delta u is q plus w.
好，Δu是多少？Δ
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w This is just q plus w. There's w, RT1 ln q has to be R T1 log of V2 over V1.
而U等于q加，那是w，q应该是。
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du We can talk about du for the system well, w that's q plus w.
我们可以讨论它的，等于q加。
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w That's u2 minus u1, and it's q plus w.
就是u2减去u1，等于q加。
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U And then if we can also determine delta u, then we know this, we know delta u is q plus w w, then we can determine work as well, right?
然后，如果我们也能定出△,然后我们知道这个,我们知道△U等于q加？
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So it's the same as q reversible plus w reversible.
它们是相等的，因此这也等于q可逆加w可逆。
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And of course, in either case, w delta u is q plus w, so it's q irreversible plus w irreversible, u being a state function it's the same in either case.
当然了，在这两个过程中，Δu都等于q加，因此现在是q不可逆加w不可逆，同时u在这两个过程中都是态函数。
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Delta u is q plus w. Delta u isn't zero.
U是q+w，△U不是零。
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U It's u, because u is to q plus w right, heat and work, but it's adiabatic. So there's no heat, exchange with the environment, and it's constant volume, so there's no p dV work, right.
什么是零？是U，因为,等于q加w，热量和功，但这是绝热的，所以系统与环境间没有热量交换；,同时它是灯体的，所以也没有pdV形式的功。
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