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W1 So I have my initial state, my final state, W1 my initial state, my final state here.
再加热，做功，对系统做的总功是。
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I'm going from V2 to V2 dv - what do you think this integral is? Right, W1 so this is easy part, zero here.
这样才保证了过程的可逆性,下面来计算，路径1的功。
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So, let's calculate w1. The work for path one.
计算这两个过程中做的功。
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So that says the q1 is the opposite of w1.
这是等温膨胀。
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Which is to say q1 plus q2 is equal to minus w1 plus w1 prime plus w2 plus w2 prime.
即q1加q2等于2,负的w1加w1一撇1,加w2加w2一撇。
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du It's an ideal gas, and that's equal to w1 prime.
等于CvdT，du，is，Cv，dT。,因为是理想气体，所以等于w1一撇。
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W2 So in this case, it's the amount of work is the area under that curve. And in this case here, the amount of work is bigger, w2 is bigger and it's the area under this curve.
这是路径2做的功,比W1要大，现在假设,我把这两条路径结合起来。
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So it's minus w1 plus w1 prime plus w2 plus w2 prime.
所以是负w1加上w1一撇1,加上w2加w2一撇。
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And delta u is equal to what we'll call w1 prime.
u等于w1一撇。
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w1 So we'll use w1 and w1 prime to describe the work involved.
所以我们用1,和w1一撇来描述过程中的功。
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Right. Delta u is zero, and it's also equal to this.
同时也等于这个，所以q1等于负w1。
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