You see the difference in electronegativity, square it, multiply it by one-quarter and raise that to the power e.
你看到了电负性的差异,开方,乘以四分之一,在移到e上去做指数。
We put all of this over the Rydberg constant, which is 2 . 1 8 times 10 to the negative 18 joules, and we want to raise this all to the 1/2.
除以里德堡常数,我们想把这些所有的再开方,所以我们最后。
And the good news was we didn't have to worry about how math did square root or anything like that, we just got it and we used it.
也可能是其他数,好消息是,我们不必担心math函数是怎样开方的,我们只要使用它就好。
So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.
我们可以发现有效的z等于n的平凡,乘以电离能除以里德堡常数,这些所有再开方,所以等于n乘以,除以RH整体的平方根。
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