We're subtracting them from one 1 and they're less than one, so this is bigger than this.
用1减去他们,结果小于,所以它大于它。
OK. If last minus first is greater than or equal to 2-- sorry, less than 2, then either look at this thing or look at that thing.
大于等于儿,抱歉,是小于二,看看这里或者那里,这就是我说的要特别小心的地方。
The strategies that are less than 67 but bigger than 45, I think these strategies are not, they're not dominated strategies in the original game.
对于选择大于45而小于67的数,我认为他们并不是,在原博弈中并不是劣势策略
On the y axis here it's the percent of people with these two conditions who have cardiovascular disease--or stroke rather 5%--less than 5% and a little over 5% with the stroke as the outcome.
轴表示患有心血管疾病的人同时患有,或不患有代谢综合征的百分比,就中风来说,分别是小于5%和略大于5%
So if n is greater than or equal to 1 and n is less than or equal to 3, let's just judge this thing a small number arbitrarily.
所以n大于等于1,并且n小于等于,我们武断的判定它为,一个小的数字。
p2 Draw any sort of line to go here, right?
大于V2,p1小于?
So the strategies below 1 and above 2 are never a best response for Player I.
也就是说小于1及大于2的策略,都不是参与人I的最佳对策
So we're throwing away all of the strategies less than 5/4 for Player I and bigger than 6/4 for Player I, which is 1? for Player I and similarly for Player II.
这样我们又剔除了,参与人小于5/4大于6/4的策略,参与人I只有1?的区间,同理可证参与人II
So in this experiment here, delta p is less than zero. You need to have this whole thing greater than zero. So delta T is less than zero as well. So if you're below the inversion temperature and you do the Joule-Thomson experiment, you're going to end up with something that's colder on this side than that side.
所以在这个实验中,Δp小于零,这全部都大于零,因此ΔT也小于零,所以如果在低于转变,温度的情况下做焦耳-汤姆孙实验,最后的结果是,这边的温度比这边低。
This strategy set--formally, Let's just simplify it here-- let's assume that for each Firm i they can set their price anything bigger than 0 and anything less than 1, just to keep life simple.
至于策略集合,我们把它简化成,假设每个公司i能,将它们的价格设定为,大于0并且小于1,仅仅为了简化处理
-- Else if n is greater than 4 and n is less than 6 -- 7 let's call it medium -- else if n is greater than or equal to 7, -- less than or equal to 10 -- let's call it "big" -- and if the user typed in zero or negative 10 or 20 or whatever, let's just use the all-inclusive else block and just say, "You picked an invalid number."
否则如果n大于4,并且n小于-,我们叫它为中间数--否则如果n大于等于,小于等于10--我们叫它为“大数“,如果用户键入了0或者-10或20或其它的,让我们用一个广泛的else子句,只需要说,“你选了一个非法的数字“
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