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Y Why don't I say int temp gets X. Let's say Y oh, sorry, X gets Y and then Y gets temp, this 2 would fail.
为什么我不说明，int，temp，=，X，让我们说明,哦，对不起，X=Y，然后，Y=temp，这两行将失败的。
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Y You don't want to rename them L and R or X and Y right because you want to call them left and right.
你不想把它们重命名为L和R，或者X和,因为你想叫它们为left和。
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For example, F x y z if I have an equation that looks like this, f of x, y, z.
打个比方，我有个这样的方程。
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All right, c p 1 dot y, x I've said assign that to the value 2, 2,0. So now c p 1 has inside of it an x and y value.
一个特定的版本，我现在命名了一个内置变量，并给它赋值了,我刚刚做的也就是给它。
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It was awkward teaching an introduction Y and probably for that reason while I was teaching Lit 300, which was then called Lit Y, Z Paul de Man was teaching Lit Z.
教入门课非常尴尬,也许正因为这样，我教文学300时，当时它还叫文学，保罗，德，曼教教文学。
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py And finally, we can look at the 2 p y, so the highest probability is going to be along the y-axis.
最后我们来看一下，概率密度最高的是沿着ｙ轴。
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This is Y today and this is Y next period.
这点表示今天的收入,这点表示下一时间段的收入
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If two arrows are equal, you cannot be longer in the x direction and correspondingly short in the y direction.
如果要使两个矢量相等,那么即使 x 分量长一些,y 分量相应地小一些也是不行的
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He still incurred -C because he ran and he also has a cost of |x-y| because he doesn't like Mr. Y winning.
他同样有-C的收益因为他参加了竞选,且他还有|x-y|的成本,因为他不喜欢Y先生获胜
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self y Notice what I also do here, I create self dot y, give it a value, and then, oh cool, I can also set up what's the radius and angle for this point, by just doing a little bit of work.
我创建了，然后给它赋值，然后，噢太酷了，通过做一点额外的工作,就可以得到点的半径和角度了，好，实际上如果。
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You're not responsible for that, you're not responsible y for correlating +1 to y, minus 1 to x.
你们不需要了解这些，你们不需要,记住+1对应。
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y Hey, try using it to store the number 13 13 through the other pointer Y.
嘿，通过另外一个指针3,试着让它存储数字。
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X Y Z It's more interestingly named an X or Y or Z.
你也可以把它命名为。
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x y z And I have another equation f of x, y, z.
若我有另一个方程。
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Now, dereferencing works on y and because the pointers are sharing 13 that one pointee, they both see the 13.
现在，解引用在y上起作用了,因为指针共享,同一个指针数据，它们两个都看到了。
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And then from that start point, get the x-value. Same thing, from that instance, get the endpoint, from that end point get the x-value, square.
取得结束点，然后取得结束点的y坐标，然后求差开平方，然后同样求的y坐标。
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