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OK, as I said, I want equality in the case of points to be, are the x- and y- coordinates the same?
好，正如我所说，我想要这个例子中的，点相等的意思是？
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At every instant, it's got a location given by the vector R; R itself is contained in a pair of numbers, x and y, and they vary with time.
在每一个瞬时,它的位置由位矢 R 给出,R 本身包含了一对坐标值 x 和 y,并且它们都随着时间的变化而变化
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Why is this much nice? Well, that's a handy piece of code. Because imagine I've got that now, and I can now store that away in some file name, input dot p y, and import into every one of my procedure functions, pardon me, my files of procedures, because it's a standard way of now giving me the input.
为什么这样很好呢？,这是一段很好用的代码,因为想象下如果我有了这段代码,我能把它用某个文件名保存起来,后缀是。py，导入到所有的处理函数中,抱歉，我的处理文件,因为这是一个标准的输入方法。
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It's going to be positive in terms of its wave function or in terms of its phase anywhere where y is positive.
只要ｙ大于零它的波函数,或者说是相位为正。
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XYZ I might as well do it as x, y, z because we are talking about something that is going in three space.
我最好设成,因为我们在讨论,三维的事物。
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The value 2 is still in what we called Y. It's now also in what we called X, but notice inside of main and here's the power.
数值2还是在y中，现在,它也在x中，但注意在main中,这是那个能力。
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Antibodies look like this, they're big proteins, if you looked at them under a microscope or if you looked at them in cartoons they're shaped like the letter Y.
抗体看起来就像这样,它们是大型蛋白,如果你用显微镜观察抗体,或者从图上看的话,它们都呈字母Y形
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So again, if you're at X and the winner is at Y, it hurts you minus the distance between X and Y, in terms of your unhappiness, about having a winner who's far away from you, winning.
再说一遍,如果你在X且获胜者在Y,它对你的伤害等于X和Y之间的距离,即,当选人和你之间的距离,这就是你在选举之后郁闷的程度
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Quite often, it's natural to pick x and y in a certain way, because starting a projectile near the Earth, it makes sense to pick the horizontal as x and vertical as y.
我们经常会很自然地选取 x 轴和 y 轴,因为如果在地表附近做抛物运动,我们通常以水平方向为 x 轴,竖直方向为 y 轴
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If it's in polar form I passed in a radius and angle and I'll compute what the x- and y- value is.
以及半径和角度,但是现在是这样的,不管我是以哪种形式。
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If two arrows are equal, you cannot be longer in the x direction and correspondingly short in the y direction.
如果要使两个矢量相等,那么即使 x 分量长一些,y 分量相应地小一些也是不行的
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px And I arbitrarily chose to put it in the 2 p x, 2pz we also could have put it in the 2 p y or the 2 p z, it doesn't matter where you double up, they're all the same energy.
我任意地选择放入至，我们也可以把它放入2py或，它与你在哪双倍填充没有关系，它们都在相同的能级。
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Um-hmm. So, it's going to be the y z nodal plane, or in other words, we can say it's any place where phi is equal to 90 degrees.
嗯，是ｙｚ平面，换句话说，是在phi等于９０度的面。
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It can be x plus some change in x plus j times y plus a change in y.
可以写成 x 加上 x 方向的变化量,再加上 y 加上 y 方向的变化量
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And actually, if I don't want to clobber, as we say, overwrite the value of my variable, ; I could declare another one and store the return value in Y; Y so now I have two ints in memory; X and Y, 3 one with two, one with three.
实际上，如果你不想彻底清除，像我们说的，覆盖那个变量的值，我可以申明另一个变量Y，并在Y中保存那个返回值;,现在内存中有两个int数，X和，一个的值为2，一个为。
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And now we get the p orbitals, remember we want to fill up 1 orbital at a time before we double up, so we'll put one in the 2 p x, then one in the 2 p z, and then one in the 2 p y.
我们到了p轨道，记住在双倍填充之前,我们想要每次填充至一个轨道，所以我们在2px填充一个然后2pz填充一个，然后2py填充一个。
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Let's test it in all possible combinations of x and y and see if we get the right answer.
来测试并看看,返回的结果正确不正确。
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If its in Cartesian form I'll pass in an x and y and compute what a radius and angle is.
来得到的这个点,我都可以得到这个点的,全部的这种信息。
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Now, suppose in fact these weren't x and y glued together, these were radius and angle glued together.
我实际也说过了,我在这里操作的是，和这两个点。
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It says, if I want to print out something I built in Cartesian form up here, says, again, I'm going to pass it in a pointer to the instance, that self thing, and then I'm going to return a string that I combine together with an open self and close paren, a comma in the middle, and getting the x-value and the y-value and converting them into strings before I put the whole thing together.
这不仅仅是个列表,它是怎么来做的？,流程是：如果我想要返回,一些已经在笛卡尔模式下建好的值，好，再说一遍，我首先要传入一个,指向实例的指针,也就是，然后我会返回一个,由开括号，闭括号,中间的一个逗号,以及提前转换为字符串格式的。
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I'm going to say, gee, p2 is the x value the same in both of them, and if it is, and the y value's the same, then this is the same point, I'm going to return true.
这样的数据对象，我会把它们命名为p1和,我会去查看，看看两个对象中，的x值是不是相同，如果相同的话，就去查看y值是否相同。
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I take the time and put it in the y equation and demand that the y I get, agrees with this y.
然后我把时间代入 y 的方程,令得到的 y 的表达式等于这一段的 y
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You've got to realize that in calculus, the symbols that you call x and y are completely arbitrary.
你应该明白在微积分中,选x还是y当符号是完全任意的
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Then, I gave you one other very important example of a particle moving in the x-y plane.
下面我再拿一个重要的例子,质点在 x-y 平面内的运动
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int Y Well, I said int X and int Y; so that gave me one square here called X, one square here ; or wherever, called Y, done, one was put in here; two was put in here, and then I called this function swap.
好的，我声明了int，X，和;,然后我这里有个正方形叫做X，一个正方形,叫做Y，完成，1放在这里;,2放在这里，然后我调用这个swap函数。
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It's got a change in x and it's got a change in y.
在 x 方向和 y 方向上分别发生了变化
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j points away from the origin in the y direction.
从原点指向 y 轴正方向
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Once I've got that, you notice I can now define a polar point, same way. Notice I've now solved one of my problems, which is, in each one of these cases here, I'm creating both x y and radius angle values inside of there.
你们注意到我现在可以，定义一个极坐标点了，以同样的方式,请注意到现在，我已经解决了我的问题之一了，也就是，在这些例子中的每一个,我在里面都创建了x，y值。
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