All right, it's so if I looked at it, sorry, IF x is less than y, THEN check to see IF x is less than z, and if that's true, print out x is the smallest.
好,代码是这样的,对不起,是不是x比y小,然后去看看是不是x比z小,如果都为真的话,显示x为最小值。
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