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Suppose f of x, y, z equals k1, that is my equation, s1 and it gives me a solution s1.
假设我的方程是这样，然后给出了一个解。
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Some others If I might have a right to X, do you have a duty to fulfill that for me?
其他的像如果我有某项权利，你有没有义务帮我实现？
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You might think it's all along x and somebody can tell me it's all along my new y axis.
你可以认为它是沿着 x 轴的,也有人会说它是沿着新的 y 轴的
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Notice in the class definition here, is there, this is the first thing that's got called, and I just called with the value for x and the value for y, and it went off and did something for me.
就在这里，这是第一个被调用的东西，我用x的值和y的值调用了它,然后这个方法继续进行，并为了做了一些操作。
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If you do that at home I think, but don't trust me, you'll find out that X is equal to a third.
如果你回去自己计算一下,你会发现X等于1/3
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We've seen in class that you get garbage values if you don't initialize something to a value so let me actually initialize x to a value.
我们在课程上了解到，如果你不给一个变量,进行赋值，它会获得一个无效值,让我把x初始化为一个值。
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I going to come back in a second to how it actually does that, but it basically says, get me x value for p 1, get me the x value for p 2, compare them, just as you would normally.
是一个类的实例,我要去取的这个实例，所关联的x值，我稍后会讲讲实际上，这里是怎么实现的，但是基本上它的意思就是，给我p1的x值。
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x and get the values of x and y attached to this thing and return them to me.
和y值然后把它们返回给我，It’s，going，to，go，off,这就是我想要的东西,我想要我的类里面有一些方法。
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Somebody who is a math major, tell me how to solve out for the X and the Y.
哪个数学专业的同学,来告诉大家如何解出X和Y的值
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I'm taking advantage of the fact that start is going to be a point, and I'm just directly saying, John give me your x-value.
我利用了开始是一个点这个事实,然后我就直接说，返回给我你的x值，因此我不知道。
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Remember last time, we wrote this simple piece of code to print out even or odd. If, you know, x, 1 it was in fact, even or odd. So let me show you what a flow chart for that would look like, because I want to make a comparison point here.
这就像这里有一些脚蹼一样,首先进行测试，然后把球这样放来让ANS加,然后回来继续测试，最终跳出循环然后打印答案。
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Z So it would be incorrect to try to assign this to a variable X or Y or Z, because it doesn't actually give me anything back.
这个是错误的，来赋值这个给变量X或Y或,因为它的确没有返回什么给我。
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Now, I prefaced this a few minutes ago about saying Professor Guttag wasn't going to like me.
结束点返回x坐标,然后把它们加起来。
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int Y Well, I said int X and int Y; so that gave me one square here called X, one square here ; or wherever, called Y, done, one was put in here; two was put in here, and then I called this function swap.
好的，我声明了int，X，和;,然后我这里有个正方形叫做X，一个正方形,叫做Y，完成，1放在这里;,2放在这里，然后我调用这个swap函数。
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So let me go back now to this expression, x=at^/2+c+bt.
让我们再回到这个式子,x=at^/2+c+bt
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Remember last time, we wrote this simple piece of code to print out even or odd. If, you know, x, it was in fact, even or odd. So let me show you what a flow chart for that would look like, because I want to make a comparison point here.
记得上节课我们写过的,那个显示奇数还是偶数的程序么，如果，你知道，x，实际上是奇数还是偶数,那么让我来为大家画个这个程序的流程图吧，因为我这里想为大家做个比较。
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And that's the following. Let's take a particle that is moving in the x-y plane, so that at one instance-- sorry, let me change this graph-- is here--oh, this is bad.
接下来,我们来看一个物体,在 x-y 平面内运动,在这个例子中,对不起,我要重画一下这个图,在这里,这画得不好
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So, the question we are going to ask is the following, "If I tell you that a particle has a constant acceleration a, can you tell me what the position x is?"
接下来要问的问题就是,如果我说某质点加速度恒为a,你能告诉我它的位移x是多少吗
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And in fact, now let me ask those two questions about this piece of code. First question is, for what values of integers-- we're going to assume integers-- but for what values of x does this code terminate? And the second question is, for what values of x does it give me back the right answer?
实际上，让我关于这块代码问两个问题,第一个问题是，对于什么样的整数值，我们会假设是整数,对于x的什么值程序,会最终终止？第二个问题是,对于x的什么值程序,会返回正确答案？
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