And so what happens when we remove these stops is that the piston slams up against the next pair of stops.

把挡板移开后活塞会,向上移动直道第二个挡板处。

麻省理工公开课 - 热力学与动力学课程节选

So in oxygen we have a similar situation where, in fact, we are not going to promote any of the electrons because we have two lone pair electrons no matter what we do.

在氧中，情况很类似，我们不能激发电子,因为无论如何我们都有两个孤对电子。

麻省理工公开课 - 化学原理课程节选

OK, so what have I done? I just added a little bit more now. I'm now running through a pair of loops. Again notice the encapsulation, that nice abstraction going on, which is what I want. Once I get to this stage though by the way, there might be more than one solution.

我现在运行了一对循环,再一次注意这个封装,抽象得很好，这就是我想要的结果,我按这种方式走到这一步的时候,可能会有多组答案。

麻省理工公开课 - 计算机科学及编程导论课程节选

If an impure object--and you will see here these overlapping pairs, if you can imagine the lower pair sort of being plunked down on top of this pair, that will give you an idea of what we're trying to convey with this image.

如果一个不纯洁的东西--看这里，这些重叠的单词，假设这两个单词,突然跑到这两个的上面，这样你就会对我们这个图示想传达的内容有个概念。

耶鲁公开课 - 旧约导论课程节选

So this is my grades on the left hand table, but now let's look at what my pair will do, what my pair will get.

我的成绩写在左边的表格里,我们再看看我对手,她会得到什么成绩

耶鲁公开课 - 博弈论课程节选

So if we take a look at nitrogen here, what you'll notice is we have thre available for bonding, - and we already have our lone pair -- one of our orbitals is already filled up.

如果我们看一下氮原子，我们注意到我们可以成3个键，我们已经有一个孤对-,其中的一个轨道已经被填满了。

麻省理工公开课 - 化学原理课程节选

So, using our simple valence bond theory, what we would expect is that we want to pair up any unpaired electrons in methane with unpaired electrons from hydrogen and form bonds.

利用简单的价电子成键理论，我们预计,要把所有甲烷中没有配对的电子,和氢原子中没有配对的电子配对来形成键。

麻省理工公开课 - 化学原理课程节选

That's what we call when we have three bonding atoms and one lone pair.

这是当我们有3个成键电子,和一个孤对时这样称它。

麻省理工公开课 - 化学原理课程节选

In particular, what grade you would get and what grade your pair would get.

具体说就是你和对手分别得什么成绩

耶鲁公开课 - 博弈论课程节选

We mean that if these are your payoffs, no matter what your pair does, you attain a higher payoff from choosing Alpha, than you do from choosing Beta.

我们说如果这是你的收益,那么不论你的对手选什么,你选择α总会比选择β,得到更好的收益

耶鲁公开课 - 博弈论课程节选

So, if we want to figure out the formal charge on the carbon, we need to take the number of valence electrons, so that's 4. We need to subtract the lone pair, what number is that? It's 2.

如果我们想算出碳原子的形式电荷，我们需要将价电子的个数，也就是四，减去孤对电子的个数，它是多少？是二。

麻省理工公开课 - 化学原理课程节选

And what we have left here is the sulfur, which will also get a pair.

剩下的是硫，它也应该得到一对。

麻省理工公开课 - 化学原理课程节选

Good; so what Clara Elise is saying--it's an important idea-- is this and tell me if I'm paraphrasing you incorrectly is no matter what the other person does, no matter what the pair does, she obtains a higher payoff by choosing Alpha.

克莱拉?埃莉斯得意思是,要是我转达的不对请提示我,不管别人怎么选,不管她对手选了什么,她选α总会得到最优的成绩

耶鲁公开课 - 博弈论课程节选

So what I'm going to do is I'm going to put me here, and my pair, the person I'm randomly paired with here, and Alpha and Beta, which are the choices I'm going to make here and on the columns Alpha and Beta, the choices my pair is making.

那么我把我写在这里,我对手,就是被随机分到的人写在这,还有是α和β,就是我要做的选择,还有我对手要做的选择

耶鲁公开课 - 博弈论课程节选

That expression, or that value, or that value, literally gets passed back out of that local environment to the value that comes back out of it. So in particular, none none what's solved returns is a pair.

这个表达或者说值，实际上是从那个局部环境中,输出来付给它的,所以solved返回的是一对值，它可以是一对。

麻省理工公开课 - 计算机科学及编程导论课程节选