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Well, I'm going to get back, let's just draw a bigger square than usual that's roughly four times the size.
嗯，返回的是，我画一个更大的方形,大致上是4倍的大小。
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Times Square... Well, Times Square has gone through a lot of changes.
时代广场……好吧，时代广场发生了许多变化。
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OK. And how do I create them? Well, the representation is, following a square bracket, followed by a sequence of elements, separated by commas, followed by a closed square bracket.
就是一个有序的序列，好，那么我们怎么创建元组呢？,好，表达式是，一个方括号，后面是一系列的元素，以逗号分开,以一个闭方括号结束，这就是我刚才所说的。
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Well, int is almost always 32 bits at least so far as we've seen so, in fact, any time I draw a pointer hence force I'm just going to draw a square as well because they are, in fact, the same size usually in memory.
嗯，int几乎总是32位的,至少我们至今所看到的是这样的，每次我用一个正方形表示一个指针,因为实际上他们，在内存中的大小是一样的。
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And what here is just a graph of the 1 s wave function going across some radius defined this way, and you can see that the probability - well, this is the wave function, so we would have to square it and think about the probability.
这里是,1s波函数,沿这个方向的图，你们可以看到概率,这是波函数，所以我们可以把它平方,并想成是概率。
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We have two, well, let me draw this is as a square.
我们现在又两个，让我用方程式写出来。
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Well, Trafalgar Square's very commercialised now.
特拉法尔加广场现在非常商业化了。
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Remember, I said when we do a bisection method, we're assuming the answer lies somewhere between Well, what is the square root of a quarter? It is a half.
记住，我提过当我们用二分法的时候,我们假设答案处于,上边界和下边界之间,0。25的平方根是多少？,是0。5。
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If I say x is 2, I want to know, what's the square root of 2, well if you're enough of a geek, you'll say 1.41529 or whatever the heck it is, but in general, this doesn't help you find the square root.
如果我说X等于，我想知道，2的平方根是多少，那么如果你足够书呆子你就会说,1。41529或者随便什么玩意儿，但是大体上，它不会帮你算出平方根。
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int Y Well, I said int X and int Y; so that gave me one square here called X, one square here ; or wherever, called Y, done, one was put in here; two was put in here, and then I called this function swap.
好的，我声明了int，X，和;,然后我这里有个正方形叫做X，一个正方形,叫做Y，完成，1放在这里;,2放在这里，然后我调用这个swap函数。
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Square root of 16, and my plot basically shows it crosses at 4 and-- well, I think that's minus 4.
我的图清楚的显示这个函数,在4和-4两个点和x轴交合。
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Well, all this time int on the blackboard I always draw an int as a square.
嗯，向来,我在黑板上用一个正方形表示一个。
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Well I'm relying on the contract, if you like, that the manufacturer of square root put together, which is, if I know I'm giving it two floats, which I do because I make sure they're floats, the contract, if you like, of square root says I'll give you back a float.
好吧我能靠一些类似合约来保证，如果这么说你喜欢的话,其实就是当求平方根的方法,获得了两个我已经确认了是浮点数的数后,这个类似合约的东西就会保证，返回一个浮点数。
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OK, once it gets to the end of that, what's it going to do? It's going to come down here and, oh. What's that doing? Well I cheated when I started. I said, somebody's giving me a perfect square, I'm looking for the square root of it. But suppose 15 I gave this thing 15, and asked it to run.
好，一旦到了循环的最后，程序会去做什么？程序会跳到这里来,噢，这是干什么的？好吧,当我开始的时候我有点小作弊的意思,我说过，我得到了一个完美的平方数,我要求这个数的平方根,但是假设下我得到的数是。
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