• The way that we can figure this out is using something called bond order, and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.

    我们可以用叫做,键序的概念来弄明白它,键序等于1/2乘以成键电子,数目减去反键电子数目。

    麻省理工公开课 - 化学原理课程节选

  • But what I'm going to tell you already is this is a case where, in fact, it's an exception to the idea that the lowest energy structure has the lowest ionization energy in the middle, and we can figure this out when we look at formal charge.

    但是我已经告诉大家这个例子,实际上,是中心原子电离能最低的结构,的能量最低这一思路的一个例外,我们可以通过形式电荷看出这一点。

    麻省理工公开课 - 化学原理课程节选

  • Let's see if we can figure out how to do this.

    看看我们能否解决这个问题。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • We can measure the heat capacity at constant volume, and now we have another term, and if we can figure out how to measure it, we'll have a complete form for this differential du which will enable us to calculate du for any process.

    我们能够测量恒定体积下的热容,这里我们有另一项,如果能够知道怎么测量它,问我们就有了这个完整的微分式,就能够对任何过程计算。

    麻省理工公开课 - 热力学与动力学课程节选

  • We'll give it a name, but by linking that T to that T, we can also figure out the same T must be exerted on this one by Newton's third law, because if this block is the only one that could be pulling this rope with T.

    我们先给它命个名,把这个 T 和那个 T 联系起来,利用牛顿第三定律,我们可以知道这个 T 也一定作用在这个物体上,因为如果这个物体是唯一,受到绳子拉力 T 的物体

    耶鲁公开课 - 基础物理课程节选

  • So, what we can do is figure out what we would expect the binding energy of that electron to be in the case of this total shielding.

    完全屏蔽的案例中,期望的电子结合,能再次记住,结合能物理上来说是。

    麻省理工公开课 - 化学原理课程节选

  • OK. So we should be able to figure this out for any orbital that we're discussing, and when we can figure out especially radial nodes, we have a good head start on going ahead and thinking about drawing radial probability distributions.

    我们可以将这种方法,用于任何轨道,当我们可以算出有多少个径向节点的时候,我们就为画出径向概率分布,开了个好头。

    麻省理工公开课 - 化学原理课程节选

  • And I know there's a lot to talk about this competition, but let's just get into listening mode here and talk about how we can figure out what the correct electron configuration is for this ion.

    我知道刚才关于这次比赛大家有很多话要聊,但是请大家先转换到听讲的模式,来看看如何才能弄清楚,这个离子正确的电子排布。

    麻省理工公开课 - 化学原理课程节选

  • If we look at our last structure here where we have nitrogen the middle, we can also figure out all those formal charges, and in this case we have plus 1 on the nitrogen, we have minus 2 on the carbon, and then we end up with a 0 on the sulfur there.

    如果我们来看看最后一个结构,在中间的原子是氮,我们同样可以计算出所有的形式电荷,而在这种情况下,氮为正一,碳为负二,而最后硫为零。

    麻省理工公开课 - 化学原理课程节选

  • We can also figure out the energy of this orbital here, and the energy is equal to the Rydberg constant.

    我们同样可以知道,这个轨道的能量,它等于,Rydberg常数。

    麻省理工公开课 - 化学原理课程节选

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