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W2 If I go backwards, to work p1 becomes the negative from what I had p2 calculated before, so this becomes minus what I calculated before for w2.
应该是,总功等于,减去,等于。
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And so just like here, w2 now q2 is minus w2, that's integral going from three to four p dV.
就跟这儿一样，现在是q2等于负，等于从第三点到第四点过程的pdv的积分。
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Which is to say q1 plus q2 is equal to minus w1 plus w1 prime plus w2 plus w2 prime.
即q1加q2等于2,负的w1加w1一撇1,加w2加w2一撇。
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W2 So in this case, it's the amount of work is the area under that curve. And in this case here, the amount of work is bigger, w2 is bigger and it's the area under this curve.
这是路径2做的功,比W1要大，现在假设,我把这两条路径结合起来。
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So it's minus w1 plus w1 prime plus w2 plus w2 prime.
所以是负w1加上w1一撇1,加上w2加w2一撇。
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Step three to four isothermal compression, w2 delta u is going to be q2 plus w2.
第三步，到四点的等温压缩，Δu等于q2加。
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q Delta u is w2 prime.
等于零，q，is，zero。,Δu等于w2一撇。
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And this is equal to w2 prime.
等于w2一撇。
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