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It's going to be the same temperature V+dV as before but the volume is V plus dV now.
将升温到跟路径1的结果一样,但是现在的体积是。
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So what we've discovered from this relationship dq that du at constant volume is equal to dq v.
从这个关系式里我们发现,恒体积时的du等于恒体积时的。
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Now we're going to hear Beach Boys, IV I guess,with a three-chord chord progression and it's going to be sub-dominant , V dominant , I tonic .
而现在我们来听听貌似是沙滩男孩，三和弦进行，然后将会是次属音，属音，和主音。
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Suppose that in 2010, v.163.com I see a car in a junk lot.
假设2010年，更多公开课到,我在废品站,看到一辆车。
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Peter's new fleet, we'll talk about his new fleet, which he oversaw and, in a very minor way, helped build himself, sails down the Don River in 1698 and takes the Turkish port of Azov, A-Z-O-V, on the Sea of Azov.
我们接下来讲讲彼得的新舰队,尽管影响不大,但他亲自监督,并且参与组建了这个舰队,舰队于1698年沿顿河顺流而下,直取土耳其的亚速港,在亚速海上
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When a particle moves in a circle, it has an acceleration towards the center of this size, v^2 over R.
当一个质点在圆周上运动时,它有一个指向圆心的加速度,v^2 / R
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argv Recompile my program, and now rerun Arg V of foo and bar.
重新编译我的程序，现在返回foo和bar的。
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Why is that? Because w and v are constant.
为什么？因为w和v是常数。
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S Formal charge equals v minus l minus 1/2 s.
形式电荷等于，V，减去，L，再减去二分之一倍的。
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V So this nR over V. And then, using the relation again, T we can just write this as p over T.
恒定温度下的dp/dT等于nR除以，再次利用状态方程，可以把它写成p除以。
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pV=RT p plus a over v bar squared times v bar minus b equals r t. All right if you take a equal to zero, these are the two parameters, a and b. If you take those two equal to zero you have p v is equal to r t.
我们就回到,也就是理想气体,状态方程,下面我们来看看,这个方程。
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V+dV And this is going to be here V plus dV.
这里是。
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As p goes to zero of p times v bar.
适用于任何气体。
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So that's I,IV,V,I.
所以是一，四，五，一。
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We'll get an expression in which there is no t; t has been banished in favor of v.
我们现在得到了一个不含t的表达式,t被v替换掉了
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If I don't show you any argument for v, it means v at time t and the subscript of 0 means t is 0.
如果我不对v做任何标志,那就表示t时刻的速度v,下标0表示的是t=0
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