Now we're going to start in with that pi 2 p orbitals, which gives us 1 each, and then two each in those, we'll go up to our sigma 2 p z orbital.
现在我们要填π2p轨道,每个1个,然后每个2个,我们我们填sigma2pz轨道。
Right, we had one from each atom, so that means we need a total of two in our molecular orbital.
对吧,每个原子有一个电子,这意味着在分子轨道里我们一共需要两个电子。
Now, compare the first element in each of these lists. Two is less than three, so two ought to be the next element of the list.
现在,比较每个列表的第一个元素,2要比3小,所以2应该是合并后列表的,下一个元素,然后你们就知道了。
The situation begins at--remember, the two sides are opposite each other in the field, probably in the morning.
战斗开始于,别忘了,战场上的敌对双方面对面列阵,也许是在早晨
Two pieces of memory actually touching each other or you touching memory that you don't actually own, in which case the computer doesn't really know what to do and just, bam.
两块内存相互覆盖,或者你覆盖了不存在的内存,那样的话计算机不知道,该怎么做,只有崩溃。
The claim is not now we've got two Napoleons who are, of course,not identical to each other.
它并不是说有两个,样子不一样的拿破仑。
I've set these two things equal to each other: I've got one equation and one unknown.
我让两个方程相等,只剩下了一个等式和一个未知数
Those are two continuous strands that wind around each other to form the double helix.
这两股主链,相互缠绕形成双螺旋
Yeah,it's regular, and with-- each chord was holding for two beats there in duple meter.
对,这是规则变化,每个和弦都维持两拍,这里一小节两拍。
Imagine two genes, two sorts of animals each containing their own gene.
想象两个基因,两种动物各自含有自己的基因。
Now in a stoplight, it only has three, one is tempted to say, variables plainly differing from each other: red, yellow and green we have two ways of thinking about the red light.
交通灯,三种灯,红黄绿,它们的颜色和彼此不能,我们有两种方式认识红灯的意思。
Each of us contains these two warring, you might say, elements within us, both self-assertion and fear of the consequence of self-assertion. The question is for Hobbes, ? how do we tame these passions?
我们每个人都有这两种,矛盾的元素,即对自负之结果的自负和恐惧,对霍布斯来说,这个问题就是,我们怎样控制情绪?
This continuity of the two scenes next to each other really does not make a lot sense to me.
就我个人而言,这两幕的衔接很说不过去。
So, these two are equal to each other as well which tells me that this derivative, Cp dH/dT constant pressure is Cp.
所以这两者也相等,这告诉我们在恒压下微分,等于。
We've got two cases where each one of those things now is isoelectric with neon.
这里我们有两个例子,现在是氖的等电子体。
And I'm going to show you an example in a 1 second, just to drive this home, but notice the characteristics. In the first two cases, the problem reduced by 1 at each step.
在前面两个例子里,每一部问题的规模缩小了,不管是迭代的还是递归的,这表明这个问题的复杂性可能是线性的。
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