They're trying to lay out an argument which is consistent and continuous and keep surprise to a minimum.
他们试图自然地建立起一个论点,使之一致,使我们的诧异最小化。
I would say, keep that to a minimum, because what the first formula tells you should be so intuitive that you don't have to cram this.
我会说,越少越好,因为对于第一个式子的内容,你应该觉得如此自然,以至于你都不用去记
And so, I need to cheat a little bit on the drawing and make sure that this minimum occurs right here.
所以,我需要在画时作点弊,以确保最小值出现在这儿。
In other words, if we don't have to worry about entropy or volume equilibrium is achieved when energy is at a minimum.
换句话说,如果我们不担心熵,和体积的平衡,那么能量就得是最小的。
So our minimum that we're going to see is that the smallest we can have for a z effective 1 is going to be equal to 1.
所以我们能够看到的,最小的有效电荷量,等于。
I'm not going to tell you what you want to do except to say, you would never pick a point below the minimum variance portfolio, right?
我不是教你怎样去组合,当然了,你不会选择一个,曲线上最小方差点以下的资产组合,对吧?
So I differentiated this object, this is my first derivative and I set it equal to 0 Now in a second I'm going to work with that, but I want to make sure i'm going to find a maximum and not a minimum, so how do I make sure I'm finding a maximum and not a minimum?
这样我就对它求出导数了,这是一阶导数,令它等于0,一会我们就要计算了,但我先确定一下是最大值还是最小值,我怎么确定是最大值还是最小值呢
So I ask you to keep that to a minimum.
所以请你们尽量小声说话
So, for example, we were talking about a threshold frequency as in a minimum frequency of light that you need in order to eject an electron from a metal surface.
举个例子来说,我们谈论的临界频率是,光从金属表面逐出一个电子,所需的最小频率。
So if we're going to eject an electron using a minimum amount of energy, that's where it's going to come from.
因此,如果我们要用最少的能量,激发出一个电子,那这个电子一定是,2,p,轨道上的。
This has happened so many times in history that governments around the world now regulate banks and tell them that they have to hold a minimum amount of reserves and have a minimum amount of capital.
这在历史上已经发生多次了,如今,各国政府都在进行银行监管,并且告诉他们,他们必须留存最小金额的准备金,以及最小金额的资本金
The only place q1 appears here is here, so when I differentiate again I'm going to get -2b and sure enough that's negative, which is what I wanted to know, just to check that when I'm finding this thing, I'm finding a maximum and not a minimum.
只有这一处有q1,因此二阶导数是-2b,它肯定是个负数了,这正是我们想得到的结果,这就验证了我们刚才得出的,是最大值而不是最小值
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