The way that we can figure this out is using something called bond order, and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.

我们可以用叫做,键序的概念来弄明白它，键序等于1/2乘以成键电子,数目减去反键电子数目。

麻省理工公开课 - 化学原理课程节选

We've played it three times, Let's try and figure out what the equilibria looked like in this game.

我们做了三次,我们试着解决,此博弈中的均衡是什么样子

耶鲁公开课 - 博弈论课程节选

The figure you are quoting in New York times which came out of a report published by a French economist who lives in India John Kenneth. And the article was by Sangota, the New York Times editor.

你从纽约时报,某篇报道上摘下来的数据,出自一名住在印度的法国经济学家,之手，他叫约翰·克南斯,该文章由纽约时报的圣郭特所编辑。

普林斯顿公开课 - 国际座谈会课程节选