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google Imagine you want to search through Google to find a particular page. You want to do it in a second. And you're going to just do it the brute force way, assuming you could even reach all of those pages in that time.
假设你想通过,搜索一个特定的网页,你想在1秒内得到结果,然后你就只管去做了,认为能在1秒内遍历遍所有的网页。
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I guess you kind of have to force yourself and make the time.
我想你要迫使自己挤出时间。
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Every time you are finding out a different force that's acting on a body with different origin.
每次你都会发现不同来源的力,作用在物体上
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How do you deal with that trade-off where you absolutely need an ad sales force but at the same time, if one person at a time, you just can't say let's go out and hire five good engineers or five good ad sales people and not have them be great?
如何做出选择，如何取舍,当你急需一批销售人员，但如果只碰见一个合适的人选，你不只能因此去找,5个差不多的工程师,或者5个差不多的广告销售？
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Now, what we saw last time is there's a brute force solution.
现在，我们上次,看过穷举法解决方案。
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Well, int is almost always 32 bits at least so far as we've seen so, in fact, any time I draw a pointer hence force I'm just going to draw a square as well because they are, in fact, the same size usually in memory.
嗯，int几乎总是32位的,至少我们至今所看到的是这样的，每次我用一个正方形表示一个指针,因为实际上他们，在内存中的大小是一样的。
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First, we got to make sure the spring exerts a fixed force every time.
首先,要保证,弹簧每次产生的力是恒定的
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Whenever there is a force, it can be traced back to a tangible material cause, which is all the time a force of contact, with the exception of gravity.
如果有作用力,那它一定能找到一个明确的实体施力物体,也就是无论何时物体受的都是接触力,引力除外
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It looks like a tautology because you're never able to show me something that moves forever at a constant velocity, because every time you don't find such a thing, I give an excuse, namely, a force is acting.
这听上去像个死循环,因为你不可能,找到永远匀速运动下去的物体,因为每当你找不到这样的物体时,我就会给出一个理由,也就是,有力作用在上面
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For example, how do I know that when I pull the spring the first time for the mass, it exerted the same force when I pulled the spring the second time for the elephant?
例如 怎样才能知道,第一次连着物体拉弹簧时,产生的力和,第二次连着大象拉弹簧时产生的力是相等的呢
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