And in this case we have three choices here in terms of what's going to be in the middle, so we need to decide that first.

而这种情况下对于哪个原子,在中间我们有三种选择，这是我们首先要确定的。

麻省理工公开课 - 化学原理课程节选

Player II has three choices, this game is not symmetric, so they have different number of choices, that's fine.

参与人II有三种选择,这个博弈不是对称的,所以他们可选策略数量不同,这无所谓

耶鲁公开课 - 博弈论课程节选

Because it takes three units where there's only four choices at each position to have at least 20 unique combinations.

因为每个位点上仅有四种可能性,只有采用三个碱基一组,才能取得至少二十种不同的组合方式

耶鲁公开课 - 生物医学工程探索课程节选

Player II has three choices left, center, and right, represented by the left, center, and right column in the matrix.

参与人II有三种选择,左中右,用矩阵的左中右三列来表示

耶鲁公开课 - 博弈论课程节选

It involves two players and we'll call the Players I and II and Player I has two choices, top and bottom, and Player II has three choices left, center, and right.

此博弈有两个参与人,分别为I和II,参与人I有两个选择,上和下,参与人II有三个选择,左中右

耶鲁公开课 - 博弈论课程节选

If I have three, I have 16 x 4 or 64 possible choices, way more than enough.

那如果是三个碱基一组,那就有16x4种,六十四种组合,那就足够了

耶鲁公开课 - 生物医学工程探索课程节选