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So that means this node 1 will have an index of 1.
所以这意味着,这个节点索引值将会为。
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And we ask, what do we get with this node?
然后我们问，这个节点我们获得的是什么？
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So if we square sigma 1 s star, we flip the amplitude so it's all positive now, but again we still have this node right in the middle.
如果我们平方1s星，我们把振幅翻转所以现在都是正的，但同样在中间有个节点。
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Yeah. And what does this node look like?
太好了，那这个节点应该是怎样的呢？
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And what is this node going to look like?
这个节点应该是什么样子呢？
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In an orbital is remember that this area right here at r equals zerio, that is not a node.
例如对于１ｓ轨道,记住这里ｒ等于０处不是一个节点。
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So this, where we start at zero is not a node, is the first thing to point out.
零点不是节点，这是第一个要指出来的，当我们。
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This is not a node because a node is where we actually have no probability density.
因为节点处是,没有概率密度的,所以。
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The point I wanted to make is that for every node, except the leaves, the leaves are the bottom of a tree in this case, are weird, right, they draw trees where the root is at the top, and the leaves are at the bottom.
你没必要看到整棵树，我想说的重点是,对每个节点来说，除了叶子节点,叶子节点指的是树的最下面的节点，电脑科学家都很奇怪,他们画树的时候根是在最上面的。
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I'm glad to hear that no one counted this r equal zero as a node.
我很高兴没听到有人把ｒ等于０这处也算作是一个节点。
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