• And then we have c, the speed of light, 2.998 times 10 to the 8 meters per second.

    然后我们知道光速等于,2,998乘以10的8次方米每秒。

    麻省理工公开课 - 化学原理课程节选

  • And then I could put a couple of plates and I could raster the beam so that when I am looking here,the beam goes back and forth about 80 times a second.

    然后我放了两个感光片,我可以检测到光束所以,当我观察时,电子束以每秒80次的速度来来回回了。

    麻省理工公开课 - 固态化学导论课程节选

  • So, keep in mind that one milliwatt is just the same as saying 1 times 10 to the -3 joules per second.

    所以,请记住1毫瓦,和1乘以10的-3次方焦耳每秒,的说法是等同的。

    麻省理工公开课 - 化学原理课程节选

  • Frequencies, how many times you go around, f is revolutions per second It's called the angle of velocity.

    频率就是一秒转多少圈,因为 f 是每秒转过的圈数,这就是角速度

    耶鲁公开课 - 基础物理课程节选

  • You don't mind watch it a second time Actually I watched it many times, on DVD in particular. Did you use the DVD?

    你们不介意再看第二遍吧,事实上我看了很多遍,特别是看DVD,你们看DVD吗?

    麻省理工公开课 - 电影哲学课程节选

  • You get 2.18 times 10 to the plus 6 meters per second, 1% which is about 1% of the value of the speed of light.

    。18*10^6米每秒,得到的速度大概是光速的。

    麻省理工公开课 - 固态化学导论课程节选

  • So, if we do this calculation for an electron, saying it moves at 10 to the 5 meters per second, then what we end up with for a wavelength is 7 times 10 to the -9 meters.

    如果我们已知电子以,10的5次方每秒的速度运动,那么做一个计算,可以得知它的波长是,7乘以10的负9次方米。

    麻省理工公开课 - 化学原理课程节选

  • Mathematically complete problem is that you can find the function x of t by saying that the second derivative of the function is equal to -k over m times the function.

    这个数学问题就是,你可以求出函数 x,只要令函数的二阶导数,等于 -k 除以 m 再乘以函数

    耶鲁公开课 - 基础物理课程节选

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定