And our job is to find out what is the mathematical description of this path, this line in p-V's case that connects these two point.
我们的任务,就是找出,描述这条曲线的方程。
We have two main cafeterias, the Ratty and the V-Dub, which are on opposite sides, South and North.
我们主要有两个食堂,一个叫Ratty,一个叫V-Dub,两个食堂一个在南边,一个在北边。
In the case of France again, they are the work of a brilliant military engineer called Vauban, v-a-u-b-a-n.
例如法国,在佩皮尼昂 里尔 蒙梅迪等地方,这样的要塞城镇随处可见
5 So similarly would there be the number 65 next to this then the corresponding number for V-I-D and then there's generally a special character at the end that looks like a zero that says end of string here.
同样,A就是,接着再填上V-I-D对应的ASCII码,在最后还有添上一个特殊的字符,有点像0,代表这是该字符串结束。
If it's a reversible process, we know the work is the area under the curve.
对可逆过程,功等于p-V图上。
So, the two most elementary ideas you learn are what is the average velocity of an object, as then ordered by the symbol v-bar.
你们学过的两个最基本的概念是,物体的平均速度,用"v拔"表示
So we've got a I chord built on the first degree of the scale, a V chord built on the fifth degree of the scale, a IV chord built on the--a IV chord built on the fourth degree, and a VI chord built on the sixth degree.
这样我们就有了建立在第一音级上的I和弦,第五音级上的V和弦,第四音级上的IV和弦,以及第六音级上的VI和弦。
and the same for favour, they spell f-a-v-o-r, we put u in it,
同样地,对于发烧这个单词,他们拼写成f-a-v-o-r,我们要加一个u在里面,
Peter's new fleet, we'll talk about his new fleet, which he oversaw and, in a very minor way, helped build himself, sails down the Don River in 1698 and takes the Turkish port of Azov, A-Z-O-V, on the Sea of Azov.
我们接下来讲讲彼得的新舰队,尽管影响不大,但他亲自监督,并且参与组建了这个舰队,舰队于1698年沿顿河顺流而下,直取土耳其的亚速港,在亚速海上
D-A-V-I-D It's not copying the F-O-O or the D-A-V-I-D.
它不是复制F-O-O,或者。
The time, in fact, is v-v0 over a.
实际上,运动时间为/a
So on the p-V diagram, then, V1 V2 p1 p2 there's a V1 here a V2 here, a p1 here a p2 here.
在p-V图上,这是。
If you solve for that, you find y-y0=v0^/, and if you put in the v_0 I gave you, which was what, 10?
如果你解这个式子,你会得到y-y0=v0^/,如果再把我给你的v0代入,那个数是多少 10
If you want to find the speed there, you put the equation v^=v0^-2g.
如果你想求出那一点的速度,可利用方程v^=v0^-2g
Path number 1 I'm going straight up in the V-T diagram.
路径1在T-V图上,竖直向上。
As long as we understand that, we can do this cancellation and this says on the left-hand side the change in the quantity v square over 2 is a times the change in the quantity x.
只要我们明白这一点,我们就可以这样做简化,在等号左边,v^/2的变化量,为a乘以x的变化量
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