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Remember, we don't do a one-to-one correlation, because p x and p y are some linear combination of the m plus 1 and m minus 1 orbital.
记住，我们不需要把它们一一对应，因为ｐｘ和ｐｙ轨道是,ｍ等于正负１轨道的线性组合。
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The power of linearity is F=k1+k2 if I come across f of x, y, z equals k1 plus k2, if it is a linear equation, I don't have to go and solve it all over again.
线性的威力是,一个方程，如果它是个线性方程，那么我就不用再去解他了。
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Now, suppose in fact these weren't x and y glued together, these were radius and angle glued together.
我实际也说过了,我在这里操作的是，和这两个点。
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Remember, we didn't hybridize the 2 p y orbital, so that's what we have left over to form these pi bonds.
记住，我们并没有杂化2py轨道，这是我们剩下的那个行成了π键。
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I'm simply saying swap X with Y, but this 2 won't work, because where are X and Y defined?
我只简单地说交换X和Y，但是这两行不起作用，因为X和Y是在哪里定义的呢？
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When t is equal to 10,000 years or 10,000 seconds, you're going to find y is some huge negative number.
当t为一万年或一万秒时,我们得到y是一个极大的负数
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He still incurred -C because he ran and he also has a cost of |x-y| because he doesn't like Mr. Y winning.
他同样有-C的收益因为他参加了竞选,且他还有|x-y|的成本,因为他不喜欢Y先生获胜
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Y Why don't I say int temp gets X. Let's say Y oh, sorry, X gets Y and then Y gets temp, this 2 would fail.
为什么我不说明，int，temp，=，X，让我们说明,哦，对不起，X=Y，然后，Y=temp，这两行将失败的。
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Now get int *y so now I'll use the board for things I can't really draw very well with the keyboard so what does the memory of my program look like at the moment?
现在，=，int，*y，现在我使用黑板,我用键盘画的不是很好,那么此刻，我程序中的内存看起来像什么？
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That's it. Again, these other p dxy dyz - or the d x y, d y z, those are going to be those more complicated linear combinations, you don't need to worry about them.
同样，这些p轨道,或者，它们是一些,很复杂的线性组合，你们，不用管它。
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px And I arbitrarily chose to put it in the 2 p x, 2pz we also could have put it in the 2 p y or the 2 p z, it doesn't matter where you double up, they're all the same energy.
我任意地选择放入至，我们也可以把它放入2py或，它与你在哪双倍填充没有关系，它们都在相同的能级。
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Z So it would be incorrect to try to assign this to a variable X or Y or Z, because it doesn't actually give me anything back.
这个是错误的，来赋值这个给变量X或Y或,因为它的确没有返回什么给我。
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Y You don't want to rename them L and R or X and Y right because you want to call them left and right.
你不想把它们重命名为L和R，或者X和,因为你想叫它们为left和。
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Consequently, for this object the position y, at any time t is known to be 15+10t-5t^.
因此,对这个物体来说,在任意时刻的位移y,就应该为15+10t-5t^
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So, that is a tricky problem to begin with because if you take this formula here, it tells you y if you know t, but no, we're not saying that.
以这个问题刚开始的时候有点难度,因为如果你要用这个公式,求y的时候就一定要知道t,但是,我们不知道
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By the way, I didn't tell you this but I think you know that I picked my origin to be here and measured y positively to be upwards and I called that 15 meters.
顺便说一下,虽然我没明确指出,但我想你们应该都知道,我把原点取在这里,并规定y的正方向朝上,我设把这里的高度为15米
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Say, Binky, I don't think dereferencing y is a good idea because, you know, setting up the pointee is a separate step and I don't think we ever did it.
你说，Binky，我不认为不关联y是一个好主意,因为，你懂的，调定指针数据是一个单独的步骤,我不认为我们这样做了。
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It becomes a 13 and that is consistent with the code and it also doesn't crash because now y has been assigned to the correct value.
它变成了一个13，这个和代码是一致的,程序也不会崩溃,因为现在y被赋了正确的值。
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And again, you might be thinking well, why didn't we actually hybridize this 2 p y orbital.
它来自1s和2p轨道，所以它是sp2，同样。
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All right, so one thing that I want to point out, which I said many, many times on Friday, and this is perhaps the last time I'll say it, but one last time is we can think about why we only see a line for the 2 p orbital, versus we don't see separate lines for a 2 p x, a 2 p y, and a 2 p z.
好的，我还要指出一个问题，这个问题我在上周五已经说了很多很多次了，这可能是我最后一次提到它，但是这最后一次让我们来考虑一下,为什么我们只看到了一条，对应于，2，p，轨道的线,而不是分别对应于，2，p，x，2，p，y，2，p，z，的线？
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