• So, in order to fill our octet, what we do is put two on the nitrogen and two on the carbon.

    因此,为了填满我们的“八隅体“,我们需要将两个放到氮上,将另外两个放到碳上。

    麻省理工公开课 - 化学原理课程节选

  • So, electron promotion does not happen in terms of nitrogen, because it would not increased our number of unpaired electrons.

    这里对于氮原子不会有电子激发,因为这不会增加,未配对电子的数目。

    麻省理工公开课 - 化学原理课程节选

  • We know nitrogen bonds multiple bonds, so let's look at nitrogen.

    我们了解氮气中有多重键,我们看看氮气。

    麻省理工公开课 - 固态化学导论课程节选

  • So what we can actually directly compare is the dissociation energy or the bond strength of nitrogen versus hydrogen.

    因此实际上我们可以直接进行比较,对氮分子与氢分子的离解能,或键的强度。

    麻省理工公开课 - 化学原理课程节选

  • So in terms of nitrogen that starts off with a valence number of 5, again we have 2 lone pair electrons in the nitrogen, and again, we have 6 electrons that are shared.

    对于氮来说,我们应该从五个价电子开始,同样,氮也有两个孤对电子,共用电子的个数也一样,是六个。

    麻省理工公开课 - 化学原理课程节选

  • We know that ionization energy is going to increase as we go across the periodic table, so that means carbon has a lower ionization energy than nitrogen which is right next to us.

    我们知道电离能会随着周期表,向右而逐渐变大,因此碳的电离能比旁边的氮要低一些,那么就像我说的。

    麻省理工公开课 - 化学原理课程节选

  • So if we take a look at nitrogen here, what you'll notice is we have thre available for bonding, - and we already have our lone pair -- one of our orbitals is already filled up.

    如果我们看一下氮原子,我们注意到我们可以成3个键,我们已经有一个孤对-,其中的一个轨道已经被填满了。

    麻省理工公开课 - 化学原理课程节选

  • So, in this case, we see that our formal charge is negative on the nitrogen, in this case it's negative on oxygen.

    那么,在这种情况下,我们看到氮的形式电荷是负的,而在这种情况下,氧的是负的。

    麻省理工公开课 - 化学原理课程节选

  • So that explains one of our glitches here, but we have another glitch, and that second glitch comes between nitrogen and oxygen.

    那么我们的第一种小偏差已经解释清楚了,但是我们还有另外一种,它在氮和氧之间发生。

    麻省理工公开课 - 化学原理课程节选

  • So this means nitrogen has low electron affinity, it doesn't actually want to gain an electron.

    这意味着氮的电子亲和能很低,它实际上并不愿意得到一个电子。

    麻省理工公开课 - 化学原理课程节选

  • So, if we took the case of nitrogen, if we add an electron to nitrogen and go to n minus, we find that the change in energy is 7 kilojoules per mole.

    如果我们以氮为例,如果我们给氮增加个电子令它变成-1价的氮,我们会发现能量的变化是,7,千焦每摩尔。

    麻省理工公开课 - 化学原理课程节选

  • So, if we talked about a nitrogen-nitrogen single versus double versus triple bond, the triple bond will be the shortest and it will be the strongest.

    因此,如果我们讨论的是氮与氮之间的单键,双键与三键,那么三键应该是其中最短的一个,同时也是最强的一个。

    麻省理工公开课 - 化学原理课程节选

  • We see that the radius is shorter, so that means that the nitrogen-nitrogen bond is going to be shorter.

    我们看到这个距离更短,这就意味着,氮与氮之间的键应该更短。

    麻省理工公开课 - 化学原理课程节选

  • So, shared electrons are the ones that are shared between the carbon and the nitrogen, so we have 6 shared electrons, and we want to take 1/2 of that.

    共用电子是那些在碳和氮之间,被它们共用的电子,那么我们有六个共用电子,然后我们要给它乘上二分之一。

    麻省理工公开课 - 化学原理课程节选

  • So we can put actually all 4 of our extra electrons in between the carbon and the nitrogen.

    因此我们可以把这剩下的,四个电子都放在碳和氮之间。

    麻省理工公开课 - 化学原理课程节选

  • So in our first structure, we would find for the nitrogen we have a formal charge 5 minus 4 minus 2, because we're starting with 5 valence electrons, so that is a formal charge of minus 1.

    那么在我们的第一个结构中,我们发现氮的形式电荷量是五减去四4,再减去二,因为我们开始有五个价电子,因此它的形式电荷量是负一。

    麻省理工公开课 - 化学原理课程节选

  • So that takes care of the hydrogen, what about between the carbon and the nitrogen?

    因此氢就被排除了,那么碳和氮呢?

    麻省理工公开课 - 化学原理课程节选

  • So, nitrogen is shown here, we know that because it has 7 electrons.

    那么这里显示的是氮,我们能看出来是因为它有七个电子。

    麻省理工公开课 - 化学原理课程节选

  • So what we see is that the formal charge on the nitrogen is 0.

    因此我们看到氮的形式电荷是零。

    麻省理工公开课 - 化学原理课程节选

  • So, let's, for example, look at nitrogen. So n 2, we can do the chart here in green, so it's the green dotted line, and what we see is that we have now defined this energy as where the 2 nitrogen atoms are separated.

    那么,让我们举个例子,看一下氮,那么氮分子,我们可以把它用绿色曲线画在这,这是绿色的虚线,可以看到,我们已经定义为零点能,当两个氮原子分离时。

    麻省理工公开课 - 化学原理课程节选

  • But for anything 7 or less, so what is the atomic number for nitrogen?

    但对于7或者更少,对于N原子序数是多少?

    麻省理工公开课 - 化学原理课程节选

  • So if we're comparing the difference between these 2 now, what you'll notice is that in nitrogen we have all half-filled 2 p orbitals, and now, once we move into oxygen, we actually have to add 1 more electron into 1 of the 2 p orbitals.

    那么如果我们来比较下它们两个有什么不同,你会发现氮的,2,p,轨道,都是半满的,现在,我们继续看一下氧,我们不得不在其中一个,2,p,轨道上,再放上一个电子。

    麻省理工公开课 - 化学原理课程节选

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