W.A.S.T.E. We're not allowed to say "waste," remember.
记住,我们不被允许说“废物“
So here's the solution for a hydrogen atom, where we have the e term here is equal to everything written in green.
这里是氢原子的解,这里的能量E项,等于绿色字体的部分。
s We are back over to E as a function of n, l, m and s, only we got there through this other torturous route.
我们回到将E作为函数n,l和,只要我们解决了这个烦人的路径。
That's good, then we go D up to E; that's another whole step.
很好,然后从D升到E,又是一个全音级
We'll talk about the Battle of the Somme, s-o-m-m-e. And the Battle of the Somme, in the first day of the Battle of the Somme, the first of July, 1916, there were 20,000 British soldiers killed.
我们会谈到索姆河战役,s-o-m-m-e,在索姆河战役,开战的头一天,1916年七月一号,20000英军士兵阵亡
So for sodium, again, we can write n e 3s1 and then 3 s 1.
对于钠,再一次,我们可以写Ne然后。
So we have s e h 2.
所以我们有SeH2。
We should call it E-flat and put it up on the E line because there's kind of rule here that you have to use up each letter name in turn, each letter name in turn.
我们应该称之为降E,把它放在E的谱线上,因为这算是一个规则,要依次使用每个字母,依次用每个字母
So what we'll end up with is boron plus, 1 s 2 2 s 2 1 s 2, 2 s 2, E and what we say is the delta energy or the change in energy as the same thing as saying the energy of the products minus the energy of our reactant here, that's how much energy we have to put into the system to eject an electron.
所以结果应该是正一价的硼,电子排布为,我们说,Δ,也就是,E,的变化量,等于生成物的能量,减去反应物的能量,这就是我们从这个系统中,打出一个电子所需要的能量。
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