printf I have my includes, standard IO's; so I can use print F, but then I had this thing called a prototype.
我包含了标准输入输出文件,所以我可以使用,然后我有这个原型。
That's true, but especially because of my parenthesization 32 over here, because I'm saying, "Do f minus 32, but then multiply it by the division on the left."
是那样的,但是特别地,因为我这里加上了括号,因为我指明,“f减去,然后它乘以左边的那个除法的结果“
Let's bind z eh let's bind z to the-- f if I could type it would help-- say, f of 3. OK?
让我们给z赋值--如果我能打字就好了-,比方说?
So path number 1 went from i, f let's call this path up here. went to f, and this is how much energy change there was.
从i出发,经过路径1到达,能量的变化是这么多。
I don't know if it actually mentions the internet but it's--the Regulation F.D. basically says that whenever a company announces information it has to be available almost instantly to everybody in the market.
我不确切F.D.条例是否涉及网络,但F.D.条例要求,任何一家上市公司对外发布公告,那么这条消息就必须,即时传达到市场上,告知每一个人
f Well, call toupper pass this lowercase F F to this function called toupper it's going to return capital F and so what do I assign to s2 bracket zero?
调用toupper函数,传递这个小写,然后返回的是大写的,那么我对s2【0】赋值多少?
F-O-O in lowercase and, in fact, foo it is buggy because I typed lowercase F-O-O and FOO yet I get back capital F-O-O as both the original and the copy and that's simply because I haven't done this correctly.
小写的f-o-o,实际上,它是有bug的,因为我输入小写的,而我得到的原始的和拷贝的都是大写的,简单说,我处理错了。
D-A-V-I-D It's not copying the F-O-O or the D-A-V-I-D.
它不是复制F-O-O,或者。
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