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qB This must be heat q B, right. So again, but now let's also look at our special function.
这个不是，这应该是热量，对吧？所以又一次，这些是我们熟悉的。
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All right. Let's consider now the second extreme case, or extreme case b, b for our helium atom.
好的让我们现在来考虑,一下第二种极端案例，或者极端案例。
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If there's no heat flow between the b and c, then I can say all right, a and c were the same temperature.
如果在与之间没有热量流动，那么我就可以说，好吧与处于相同的温度。
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I want to then do, I need to find the square root b squared plus h squared, right?
我接下来要求b的平方和h的平方,的和的平方根对不对？
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If our date for him, which is very problematical, is right roughly, then by certainly 700 B.C.
如果我们追溯他所处的时代的话,大概是在公元前700年,当然这有待确认
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B In fact, it's even a question whether A is A, but it's certainly not B, right? This much we know. In the grammatical sense there is no sort of mystification about the metaphor.
实际上，人们甚至对A是不是A都有疑问，但肯定不是，是吧，我们都知道这点，而从语法的角度来看,并没有像暗喻一样的神秘化。
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b Star B in the last line of code now means find B, 1 2 3 all right, that's 1, 2, 3.
在最后一行的*b意思是查找，好的，那是。
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Roughly speaking, a sixth of the class are going to end up with A's, a sixth are going to end up with A-, a sixth are going to end up with B+, a sixth are going to end up with B, a sixth are going to end up with B-, and the remaining sixth, if I added that up right, are going to end up with what I guess we're now calling the presidential grade, is that right?
总体来说,六分之一的人会得到A,六分之一的人会得到A-,六分之一的人会得到B+,六分之一的人会得到B,六分之一的人会得到B-,剩下的六分之一,如果我没算错,这些人将会得到,传说中的"超优"成绩
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pV=RT p plus a over v bar squared times v bar minus b equals r t. All right if you take a equal to zero, these are the two parameters, a and b. If you take those two equal to zero you have p v is equal to r t.
我们就回到,也就是理想气体,状态方程,下面我们来看看,这个方程。
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Minus p, right? But in fact, if you go back to the van der Waal's equation of state b here's RT over v minus b.
再减去p，对吗，但是实际上，如果你代回范德瓦尔斯气体的状态方程,这里是RT除以摩尔体积减去。
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Yeah. Actually, I think I want b minus k equal to 1. Right?
对，实际上，当b-k=1的时候就该停下来了对不对？
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All right, so if we think about b h bond here, again, it's the sigma bond, and we're going to say it's a boron 2 s p 2 hybrid orbital interacting with a hydrogen 1 s orbital.
这可以告诉我们，为什么它倾向于周围只有6个电子，好了，考虑一下这里的BH键,同样的，它是sigma键,我们说。
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In B it isn't, it's Cv times T2 minus T1, right.
在B中不是，而是Cv乘以。
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Right. A is 2; B is 1, and yet somehow the process gets undone.
对的，A是2，B是，但是不知为何那个处理没有完成。
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This is 3 plus 3 plus t of b minus 2. Right?
+3+t对不对？
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Yeah. You're jumping slightly ahead of me, but basically, I'm done when this is equal to 1 right? Because I get down to the base case, so I'm done when b u is over 2 to the k is equal to 1, and you're absolutely right, that's when k is log base 2 of b.
因为这就是最基本的情况了，因此当b/2的k次方等于1的时候就停止了1,你说的太对了，就是k等于b的以2为底的对数的时候,你们都坐的挺靠后的啊，我不知道是不是我讲的不太明白？
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b times. So I've got to go 3 b steps. All right I've got to go through the loop b times I've got three steps each time, and then when I pop out of the loop, I've got two more steps. All right I've got the initiation of answer and the return of it.
好，我一共执行了b次循环,每次循环内部进行了三次基本操作,当跳出循环后还有两个基本操作，因此这个初始的答案就是,2+3b次基本操作,来完成这个循环。
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So delta u B is Cv times T2 minus T1, right.
是Cv乘以，对吧？
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So let's look at b search. All right?
那么让我们来看看b，search，这个方法？
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Sorry. b times. You're right.
答得对，b次。
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b OK. In this example I'd use b. All right, as b get-- b is the thing that's changing as I go along here, but it could be things like, how many elements are there in a list if the input is a list, could be how many digits are there in a string if the input's a string, it could be the size of the integer as we go along. All right.?
好，在这个例子里我会用，因为b是一直在变的东西,但是也可能是如下情况：,如果输入是数组的话,变化的就是数组的元素数，如果输入是字符串的话,变化的就是字符串的长度，如果是integer的话,可能就是这个数的大小，对不对？
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You know, that's nice, right?
因为这样即使b是奇数，b-1也是偶数？
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