Well, that process occurs in a series of steps and one of those kinds of steps is shown here.

这个过程的发生包含一系列步骤,而这些步骤中的一个步骤即如图所示

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And so in theory after just 2 or 3 steps you were in order of magnitude farther along in this counting process than I would be because I'd still be on person literally 3 or 4.

因此从理论上说,经过这样短短的两三个步骤,你们就有了分级次序，比我数数快多了,因为我才数到第三四个人。

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Our goal is to take problems and break them down into these computational steps, these sequence of instructions that'll allow us to capture that process.

我们的目标是得到问题,然后将问题分解为这些计算步骤，这些指令集,可以让我们看到这个过程。

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OK, now we can do the process in two steps.

好，我们可以把过程分为两步。

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It's hard to answer questions and whatnot and you don't necessarily have access to the same tools unless you yourself go through the process of configuring your machine manually by following many long sequences of steps.

所以很难说会出现什么情况,你们不能,用同一台机器，除非你们自己按照一系列,冗长的步骤手工配置,你们自己的电脑。

哈佛公开课 - 计算机科学课程节选

But that merging process only takes N steps, N*log N so that's N times log of N. Now, it's a little tricky to reason through this perhaps the first time, let's just take a very simple example and see if we can do a little sanity check here.

但这个合并过程只需要N步，所以时间复杂度是,第一次对此进行推论可能会有点儿棘手，我们举一个简单的例子,看看我们能否做一些完整性的检查。

哈佛公开课 - 计算机科学课程节选

I'm reminded of the confirmation screen here and that's not too bad, then we put in the card and we click confirm and then finally we see the swap Then finally literally nine steps later the ticket comes out of the machine and then, frankly, had to go through the process of where to put the ticket in the machines.

这里出现了确认画面,那还不是太坏，然后我们把卡插进去,点击确认，然后我们看到了那个,函数。，swap，function。,【笑声】然后最终经过9个步骤,票从机器中出来了，然后，需要找出从哪里,把票放到机器中去。

哈佛公开课 - 计算机科学课程节选