So let's have a clicker question here on how many total pi bonds do you expect to see in benzene?
让我们来做个课堂习题,你们觉得苯环里有一共多少个π键?
So what we see is that those six pi electrons are actually going to be de-localized around all six of those atoms.
我们看到,六个π电子会,巡游在所有六个原子周围。
And we can simplify this expression as saying negative e squared over 4 pi, epsilon nought r squared. Epsilon nought is a constant, it's something you might see in physics as well.
也会遇到它,在这里,你可以就把它,理解为一个转换系数,我们需要做的。
So if I try to rotate my 2 atoms, you see that I have to break that pi bond, because they need to be lined up so that the electron density can overlap.
如果我要试着转动两个原子,你会看到我必须要打破一个π键,因为他们需要连接起来,让那些电子能够重叠。
So it's very important to be keeping in mind that any time you see a double bond, you have a pi bond there, so you're not going to see any rotation around the bond axis.
所以你们要记住,任何时候你们看到一个双键,这里面有π键,你们不会看到关于键轴的任何转动。
So, we're going to see two pi bonds.
我们可以看到两个π键。
When we look at this angular part, we see that it's always the square root of 1 over 4 pi, it doesn't matter what the angle is, it's not dependent on the angle.
当我们看这角向部分,可以看到它总是等于1除以4pai开根号,这和是什么角度没有关系,它和角度无关。
Another thing I want to point out about every sigma orbital that you see, and it will make more sense when we contrast it with pi orbitals later.
另外一个我要指出的事情就是,关于每个sigma轨道你能看到,当我们把它和π轨道对比的时候会看的更清楚。
You can see that we have two unpaired electrons in this molecule here one in the pi 2 p x star, and one in the pi 2 p y star orbital.
你们可以看到我们这个,分子力有两个未配对电子,一个在π2px星,一个在π2py星轨道。
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