So, the work for this process is the integral, pdv or minus the integral, V1, V2, p dV.

此过程中的做功等于负的积分，从v1到v2，外部。

麻省理工公开课 - 热力学与动力学课程节选

Adiabatic q equal to zero. It's also delta H 0 which is zero. The two didn't necessarily follow because remember, delta H is dq so p is only true for a reversible constant pressure process.

在这个过程中ΔH等于,绝热的所以q等于0，而ΔH也等于,这两个也不一定有因果关系,因为，记住，ΔH等于dq只有在恒压。

麻省理工公开课 - 热力学与动力学课程节选