-
p2 One of them is going to end up at pressure p2 p3 and the other is going to end up at pressure p3.
其中一种末态压强为2,另一种末态压强为。
-
p2 So they're both p2. external is p2 p2 V2 T2 and I have p2, V2, T2, on the other side.
都是2,这样末态是。
-
p1 But if I say, are p 1 and p 2 the same point, it says yes.
和p2是不是同一个点，It，says，no。,返回的结果是肯定的，在这里我有个要强调的点，这个例子里发生的是。
-
So they're going to P1, will the price of Firm 1, and P2 will be the price of Firm 2.
所以P1代表,公司1的价格,而P2代表公司2的价格
-
and when we remove one of the weights, p2 this gives an external pressure p2.
外部压强，变为。
-
p1 V1 Initial find -- there are many ways p2 V2 V1 I can get from one state to the other.
初态的氩气状态为,末态为。
-
There's p1 here, and p2 here So I'm starting at p1, V1. I'm starting right here And I'm going to end right here.
它的分子间作用力很小,十分接近理想气体,对它做一个压缩过程。
-
So now, instead of having p external p2 equals to p2 here, I put p1 and I let this whole thing go reversibly.
也就是说,现在开始的外界压强不是，而是p1，整个过程都是可逆的。
-
p2 It's taking the name p 1 and it's changing its value to point to exactly what p 2 points to.
我要把p1赋值为1,这个操作有什么用呢？,这个操作把p1这个名字的,指针的值改变让它。
-
Every time you do the experiment T in equilibrium with the heat bath at T, v2 you'll get the same p2 and V2.
与热库相接触的每次实验中,达到热平衡后的温度都是，压强都是p2，体积都是。
-
p2/p1 Then I'm going to get, be left with a p2 over p1.
于是右边剩下。
-
Then you take p1 to p2 with V constant.
图上画出来就是这样。
-
p2 It would stop there because we've chosen p2.
因为我们选的压强是。
-
I take V1 to V2 first, keeping the pressure constant at p1, then I take p1 to p2 keeping the volume constant V2 at V2. Let's call this path 1.
容易计算的路径，第一条路径，是首先保持压强不变,体积从V1压缩到。
-
p2 p1 is greater than p2. Then I want to reverse direction of time. I want the arrow of time to go so that the gas goes from p2 to p1.
一直推，一直推，p1大于,接下来我想让时间倒流,让气体从p2到p1。p2比p1小。
-
I'm going to say, gee, p2 is the x value the same in both of them, and if it is, and the y value's the same, then this is the same point, I'm going to return true.
这样的数据对象，我会把它们命名为p1和,我会去查看，看看两个对象中，的x值是不是相同，如果相同的话，就去查看y值是否相同。
-
It's nR log of p2 over p1 for the process where there's a pressure change.
结果是dS等于nR乘以p2除以p1的对数,这是对压强变化的结果。
-
So on the p-V diagram, then, V1 V2 p1 p2 there's a V1 here a V2 here, a p1 here a p2 here.
在p-V图上，这是。
-
I've got another little thing here that I'm going to use a little later on that just prints out values of things.
给我p2的x值,对它们进行比较,就像我们通常会做的那样。
-
If P2 is actually above the monopoly price, then what's my best response in that case?
如果P2真的高于垄断价格,我的最佳对策是什么
-
And so, we can rewrite this as the work nRTln is equal to minus nRT log p1 over p2, nRTln or nRT log p2 over p1.
因此我们可以把这个式子改写一下,功等于负的，或者。
-
This is a positive number, p1 is smaller than p2.
这就是系统对外界做的功。
-
OK, we're going to do this reversibly, which means we're going to slowly change the external pressure very, very slightly at a time, so that at every point we're basically in equilibrium, p2/ until the pressure reaches a new smaller pressure p2.
整个过程保持可逆，外界压强,变化得很慢，每一个瞬间,都保持平衡，直到压强减小到末态值。
-
p2 I'm going to set that equal to p2.
现在外界压强为。
-
so we know how to do this, and we know this thing when it hit these stops, v2 the pressure with p2, and the volume was V2.
所以我们知道怎么计算，当活塞到达这两个挡板时，压强是p2，体积是。
-
p2 There is going to be an internal pressure where T1 p1 is less than p2 and there's V1 and T1 here.
内部气体压强p1小于,体积为V1，温度为。
-
p1 And p2 is less than p1, 1 so this number right here is less than 1.
由于p2小于，这个数小于。
-
p1V1/R That p2 V2 over R, and then I have p1 V1 over R, the R's cancel out.
就是p2V2/R除以，两个R消掉了。
-
And I'll give it an x value of 3 3 and a y value of 4.
一个笛卡尔坐标3,然后给p2的x坐标赋值为。
-
External pressure is p3. It's higher than p2.
外部压强为p3，比p2大。
应用推荐