So if you're trying to make a more complicated organic molecule carbon-carbon bonds are one of the most difficult things to make in organic chemistry, and it turns out that c n minus is a very reactive molecule, so it's a good way, even though we'll go over some drawbacks in a second, it is a good way to make carbon-carbon bonds.

如果你要合成一个更复杂的有机分子,碳碳键是有机化学中,最难制造的键之一，而实际上氰离子是一种具有很高活性的分子，用它是一个好办法，尽管我们一会儿将看到它的一些缺点，但它的确是一个制造碳碳键的好方法。

麻省理工公开课 - 化学原理课程节选

Well, it turns out C, like a lot of languages, comes out of the box with a whole bunch of built-in variable types.

在C语言还有其他一些编程语言里，都会有一大堆,固定的变量类型。

哈佛公开课 - 计算机科学课程节选

All right, so that's just solving out the algebra, so we're saying what q solves, a - c over 2b - q2 over 2 = 0.

没错,只需要解出当,/2b-q2/2=0,时q2的值即可

耶鲁公开课 - 博弈论课程节选

We've got some chords set out and we're going to-- we've got some chords set out here and we're in the key of C at this point, and we're going to hear Beethoven go to a tonic chord, then a sub-dominant chord, then a tonic chord, then a dominant chord and so on.

我们看到有一些和弦-,而我们现在在C调的位置上，然后听贝多芬的主音和弦，然后是次属音和弦，然后是主音和弦，接着是属音和弦，如此往复。

耶鲁公开课 - 聆听音乐课程节选

She costs C for sure, that's a wash because B, the way we've worked things out, B was $2, C was $1, So B/2-C is a wash.

她承担C的成本,收益是零,因为B,按我们设定的金额,B是2美元,C是1美元,所以B/2-C是零

耶鲁公开课 - 博弈论课程节选

What q2 makes this equal to 0 and Katie's answer is solving out the algebra here is that q2 that solves this must be a - c over b.

2为何值时这个算式等于0呢,凯特回答其实就是算出这个的解,即,q2=/b

耶鲁公开课 - 博弈论课程节选

And I don't quite remember from reading or from class how big these things are, well, it turns out -- and this is sometimes useful, later on more likely than now -- but C has a size of operator that takes an argument in parenthesis and it will tell you how much space is used to store that particular data type.

我不太记得类中的这些类型,是多大的，嗯，结果是--这个在以后比现在，可能是更有用的--不过C语言中有个sizeof的操作符,其中括号里有一个参数,它会告诉我们，要存储一个类型的数据,需要占用多大空间。

哈佛公开课 - 计算机科学课程节选