So, why don't you go ahead and tell me, keeping that in mind, which atom in terms of h c or n would you expect to be in the center of hydrogen cyanide?
那么,请大家来告诉我,并且记住它,你认为氢,碳和氮中哪个原子,应该在氰化氢的中间呢?
-- Else if n is greater than 4 and n is less than 6 -- 7 let's call it medium -- else if n is greater than or equal to 7, -- less than or equal to 10 -- let's call it "big" -- and if the user typed in zero or negative 10 or 20 or whatever, let's just use the all-inclusive else block and just say, "You picked an invalid number."
否则如果n大于4,并且n小于-,我们叫它为中间数--否则如果n大于等于,小于等于10--我们叫它为“大数“,如果用户键入了0或者-10或20或其它的,让我们用一个广泛的else子句,只需要说,“你选了一个非法的数字“
n And these are known as anions. It has the n, which might conjure up negative, or anion and minus both have five letters.
这些就是负离子,有,能让我们想起,负,这个字,或者负离子和负号都是5个字母。
n Alright. So if n is less than or equal to 1, return n. Well that's not right, right?
好吧,如果n小于等于1,它会返回,这里不对,是吧?
So another way to say that is, in a sense, if we're thinking about the excited state of a hydrogen atom, the first excited state, or the n equals 2 state, what we're saying is that it's actually bigger than the ground state, or the 1 s state of a hydrogen atom.
换句话说,如果我们激发一个氢原子,第一激发态或者说n等于2的态,我们说它比氢原子基态,或者说1s态要大。
It's now exactly that power from which Milton has been excluded by virtue of his blindness -- light: "Hail holy Light, offspring of Heav'n first-born, / Or of th' Eternal Coeternal beam May I express thee unblam'd?"
而是弥尔顿已经被失明剥夺的一种力量,圣光,你是上帝最初的产物,永恒的光束,我是否可以向你表达我无限的敬意“
He constantly warns his son, who was kind of an n'er do well, that, "You better work hard, " Or, "You better work a little harder and pay more attention to what you're doing.
他不断提醒那一事无成的儿子,"你要加倍用功,哪怕只是稍微用点心,对你做的事要更上心
So,if you take number one--but we don't have to go through them all and I assure you we won't--if you take number one, the Ain,a-i-n,it's named after a river; or if you take number two,the Aisne,a-i-s-n-e, it's named after a river; and how many hundreds of thousands of people died along there in World War One or,you take number three,the same thing,Allier.
如果你看第一个省,我向你们保证,我们不用挨个了解,看第一个省,安省,a-i-n,来自一条河的名字,或是第二个埃纳省,a-i-s-n-e,来自于一条河的名字,有成千上万的人在这里死于,第一次世界大战,第三个,阿列省
I get the int and store it in n. The switch statement takes inside its parenthesis an int or a char or some primitive type.
我得到一个整数并把它存储,到n中,switch语句的圆括号里可以是一个整数,或者一个字符或其他的基本类型。
When we talk about the n equals 2 state, we now have 2 squared or 4 degenerate same energy orbitals, and those are the 2 s orbital.
当考虑n等于2的态时,我们有2的平方,或者4个简并能量的轨道,它们是2s轨道。
Now I'm in better shape, right? Especially for really large n or for a lot of k, because now in general, this is going to be smaller than that.
很大的k也大的情况,因为这样这就比这个小了,这种情况是分摊。
printf So thus far, the things I put David between quotes are just simple things like David or David backslash N, but what if I want to do call my self David in quotes, right?
像我们前面提到的,我们把要显示的东西放在双引号之间,譬如,或,David反斜杠n,但是如果我自己的名字本来就叫,“David“
We're getting further away from the nucleus because we're jumping, for example, from the n equals 2 to the n equals 3 shell, or from the n equals 3 to the n equals 4 shell.
我们将会离原子核越来越远,因为我们在跃迁,比如从,n,等于,2,的壳层到n等于,3,的壳层,或者从,n,等于,3,的壳层到n等于,4,的壳层。
So if n is greater than or equal to 1 and n is less than or equal to 3, let's just judge this thing a small number arbitrarily.
所以n大于等于1,并且n小于等于,我们武断的判定它为,一个小的数字。
Again, the reason for that is because the energy only depends on the n value here, it doesn't depend on l or on m.
因为,能量,只和n的值有关,与l和m的值无关。
So I'm not going to worry whether this item is a vase or a watch or painting I'm just going to say it's the n'th element.
所以我不用担心这个物品,是花瓶还是手表或者油画,我只要说这是第n个元素就好。
So that's the 1 s orbital - we have n squared or 1 degenerate orbitals.
所以这是1s轨道,我们有n平方,或者1个简并轨道。
to the n, every value in the 1 bit vector we looked at last time is either 0 or 1. So it's a binary n number of n bits, 2 to the n.
从2到n,我们上次看到的,位向量的每个值不是0就是,所以它是n,比特的二进制数,从2到。
So if N is not less than 2, that is I have two elements or more in which case there's definitely some sorting to be done.
因此如果N不小于2,也就是有2个或更多的元素,那当然是需要做排序的。
And when we make these comparisons, one thing I want to point out is that we need to keep the constant principle quantum number constant, so we're talking about a certain state, so we could talk about the n equals 2 state, or the n equals 3 state.
当我们做这些比较时,我想指出的一件事是,我们需要保持常量原则,保持量子数是常数,所以我们在讨论一个确定的态时,我们可以谈论n等于2的态,或者n等于3的态。
If they type in bogus characters, it's going to yell at them and make them retry, and eventually I'm going to get handed back an int, which I'm storing in n. Well, if I actually want to judge this number based on its magnitude, well, I can say now, "If n is greater than or equal to one."
如果他们键入了不合法的字符,它将对他们叫喊,然后叫他们重试,最终我将,得到一个int数,它是存储在n中的,好的,如果我的确想要根据它的量级来判定这个数字,好的,现在我可以指明,“是否n大于等于1“
So, for example, we could talk about the n equals 2 state, so that's this state here, and it's also what we could call the first excited state. So we have the ground state, and if we excite an electron into the next closest state, we're at the first excited state, or the n equals 2 state.
例如,我们可以考虑n等于2的状态,它在这里,它也被称作是第一激发态,我们有基态,如果我们把一个电子,激发到它最近邻的态,那就是第一激发态,或者n等于2的态。
So I propose this as a new algorithm for sorting N elements and being 8 in this case or really a thousand in the case of the phonebook, or anything of larger size.
所以我提出一种新的算法,来解决N个元素的排序问题,在这个问题中N是8,在电话簿的问题中N是一千,或者是大规模的任何问题。
So the take away is that if the user actually gives me two or three or four or whatever, this is this expression "is n less than 1" is going to evaluate to false if it's actually two or three or four or whatever.
所以先不管用户实际上给我,3,4还是其他数,这个表达式,“是否n小于1“将被评估为错误的,如果输入额是2,3,4或其它的数。
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