And in fact if I go off and run this, OK, what I was printing here was s 1 dot length, and that's -- What is it doing?
他们就是一些有结构的实例,实际上如果我去运行下这个,好,我这里输入的?
A gig is 10 to the 9, so it does two operations in the length of time it takes light to get from one foot off the table down to the table. That's amazing.
因此光行进一英尺的,时间内电脑可以,进行两次基本运算,这太神奇了。
So if I start off with a list of length n, how many times can I divide it by 2, until I get to something no more than two left?
我能够除以多少次2呢?,直到我得到的长度不超过2么?,对数次,对吧?就像刚才那位同学说的那样?
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