And in terms of radial nodes, we have 2 minus 1 minus 0, so what we have is one radial node.

对于径向节点，我们有２减去１减去０,所以有一个径向节点。

麻省理工公开课 - 化学原理课程节选

Yup, so one total node, 2 minus 1 is 1, and that means since l is equal to 1, we have one angular nodes, and that leaves us with how many radial nodes?

一个节点，２减去１等于１,因为ｌ等于１,我们有一个角向节点，那剩下径向节点有多少个呢？

麻省理工公开课 - 化学原理课程节选

5 0 The first node will be the to-pull 2, 5 and 0.

第一个节点是可获取的物品。

麻省理工公开课 - 计算机科学及编程导论课程节选

Yup, I heard one, so 2 minus 1, one total node.

嗯，我听到有人说１个，２减去１，１个节点。

麻省理工公开课 - 化学原理课程节选

So what we end up with is one radial node for the 2 s orbital of hydrogen, and we can apply that for argon or any other multi-electron atom here, we also have one radial node for the 2 s orbital of argon.

那意味着它们都是径向节点,所以我们得出的结论是，氢的2s轨道是1个径向节点,我们可以将它应用，到氩或者任意一个多电子原子,对于氩的2s轨道。

麻省理工公开课 - 化学原理课程节选

We can look at the 2 p, which should have one radial node, and we just figured it out for the, excuse me, 3d for the 3 p has one radial node, and for the 3 d here, we should have zero radial nodes, we just calculated that.

我们看2p，它有一个节点，我们已经知道对于，不好意思，是3p有一个节点，对于，它应该没有径向节点，我们刚刚算过这个。

麻省理工公开课 - 化学原理课程节选