May no fate willfully misunderstand me And half grant what I wish and snatch me away not to return.
别来个命运之神,故意曲解我,只成全我愿望的一半,把我卷了走。
.. That person-- I should have maybe included that in the diagram-- that person could get 5% return with no risk.
那种人-,我也许该把种情况也包含到图里的-,他能够获得5%的无风险收益。
It says, well I'm going to print out first and last just so you can see it, and then I say, gee 2 if last minus first is less than 2, that is, if there's no more than two elements left in the list, then I can just check those two elements and return the answer.
然后它计算了尾点和开始点的差,如果小于2的话,也就是说数组中的元素小于等于,我对这两个元素进行比较,然后返回结果就可以了,否则的话,我们就去寻找中值点,注意它是怎么实现的,首先这个指向一个列表的开头。
There's no return statement.
这里没有返回语句。
Where even if you can find somebody who's going to be a first quartile manager, there's almost no difference between the first quartile return and the third quartile return.
即使你能找到一位,一流的经理人,但在债券市场收益中,第一和第三个四分位数之间几乎没有区别
You'd have a higher expected return with no more variance.
你的预期收益率提高了,但风险没有增加。
So, the optimal thing to do if you live in a world like this n is to get n as large possible and you can reduce the standard deviation of the portfolio very much and there's no cost in terms of expected return.
如果现实中也这样简单的话,那么你就尽量增大,这样就能让投资组合的标准差,就会大大降低,从预期收益率的角度来看,这样做的成本是零。
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