So this line or these lines of code up here are arguably constant time steps to say if N is less than 2 in return, that it will always take maybe one step, maybe two steps, some number of fixed CPU cycles.

如果N小于2并返回,那么这些行所对应的代码,通常只需要执行一步，或者两步，具体数字与CPU周期有关。

哈佛公开课 - 计算机科学课程节选

n Alright. So if n is less than or equal to 1, return n. Well that's not right, right?

好吧，如果n小于等于1，它会返回，这里不对，是吧？

麻省理工公开课 - 计算机科学及编程导论课程节选

Suppose someone has been investing money for n years and xi is the return on the investment in a given year.

假设有人投资了n年,Xi是第i年的收益率

耶鲁公开课 - 金融市场课程节选

So given some input of N elements, first, if N is less than 2, I return immediately.

给出N个元素的一些输入，首先，如果N小于,就立即返回。

哈佛公开课 - 计算机科学课程节选