He urged revival of the slave-trade in the late 1850s, and he developed a theory of what he called warranteeism--w-a-r-r-a-n-t-e-e-I-s-m.
他促成了十八世纪五十年代后期,奴隶交易的复苏,还自己发明了一套理论,名为抵押品主义
And I know a lot of people over at NYU for N Tisch, and it's very highly competitive.
我认识很多人为了N Tisch去纽约大学,竞争相当激烈。
n If you want a literal percent, it's %% and then backslash n.
如果你想要一个百分比常量,就用%%,然后,反斜杠。
So, it turns out that n is not the only quantum number needed to describe a wave function, however. There's two more you can see come out of it.
事实上,n不是描述一个波函数需要的,唯一的量子数,你们可以看到,还需要,两个量子数。
So I have n operations log n times, n log n there we go, n log n. Took us a long time to get there, but it's a nice algorithm to have.
所以我log,n遍的n次操作,就得到了,虽然花了不少时间得到了这个结论。
If you invented it, we'd call it whatever your name is, but this is the guy who invented it, so it's called a Newton, usually denoted by a capital N.
如果是你发明的,我们就用你的名字当单位,但这个单位是他发明的,所以叫它牛顿,一般用大写字母 N 表示
So it's a more specific version of the equation where we have the n final equal to 2.
当我们令n等于2时,使这个这个方程变成更具体的版本。
So if n is greater than or equal to 1 and n is less than or equal to 3, let's just judge this thing a small number arbitrarily.
所以n大于等于1,并且n小于等于,我们武断的判定它为,一个小的数字。
We can think about the Lyman series, which is 1 where n equals 1. We know that that's going to be a higher energy difference, so that means that we're going to be in the UV range.
我们可以来看看Lyman系,也就是n等于,我们知道它的能量差更大,所以它在紫外光区内。
n l So negative e, which is sub n l, because it's a function of n and l in terms of quantum numbers.
也就是负的,E,下标是,因为它是一个,关于量子数,n,和,l,的函数。
This should make sense to you, because they don't, in fact, want to gain another electron, because that would mean that electron would have to go into a new value of n, a new shell, and that's really going to increase the energy of the system.
这对大家来说应该容易理解,因为它们实际上不想得到另一个电子,因为这意味着这个电子不得不,到一个新的,n,值更大的壳层上去,这将会增加系统的能量。
But that merging process only takes N steps, N*log N so that's N times log of N. Now, it's a little tricky to reason through this perhaps the first time, let's just take a very simple example and see if we can do a little sanity check here.
但这个合并过程只需要N步,所以时间复杂度是,第一次对此进行推论可能会有点儿棘手,我们举一个简单的例子,看看我们能否做一些完整性的检查。
So I'm not going to worry whether this item is a vase or a watch or painting I'm just going to say it's the n'th element.
所以我不用担心这个物品,是花瓶还是手表或者油画,我只要说这是第n个元素就好。
to the n, every value in the 1 bit vector we looked at last time is either 0 or 1. So it's a binary n number of n bits, 2 to the n.
从2到n,我们上次看到的,位向量的每个值不是0就是,所以它是n,比特的二进制数,从2到。
And when you're switching n's, you're actually getting quite a bit farther away.
而当你改变,n,的大小时,实际上每一步你都会变远了很多。
C-A-N-S-U An S in the side so Cansu, that was spelled C-A-N-S-U.
有一个S喔。
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