That would put you out here; you would have very much more return, but you'd have more risk.

那就会落在这个点上;,你可能有非常高的回报，但你的风险也增加了。

耶鲁公开课 - 金融市场课程节选

They're plainly interrelated in a variety of ways, but it's more to the question of determinism I want to return today.

在很多方面他们都相互联系，但是今天我要多谈点有关决定论的问题。

耶鲁公开课 - 文学理论导论课程节选

And so it's usually the case that you can get a higher return if you're willing to take more risk.

同样很常见的例子是,所以如果你愿意冒高风险,你可能就会有高回报。

麻省理工公开课 - 计算机科学及编程导论课程节选

The more you do that, the quicker you're able to return from wondering about to your breath.

越是这么做，越能更快恢复呼吸,而不再神游。

普林斯顿公开课 - 人性课程节选

We will return on Monday and do yet more powerful things with this.

我们将在下周一,用它做更有用的东西。

哈佛公开课 - 计算机科学课程节选

And so what I'm going to do the next day is return to this discussion, and take a look at a more rational view of the chemical world. So, we'll see you on Friday.

我下一次要做的就是,继续这个讨论，并且观察一个更为理性的,关于化学世界的观点，周五见。

麻省理工公开课 - 固态化学导论课程节选

You'd have a higher expected return with no more variance.

你的预期收益率提高了，但风险没有增加。

耶鲁公开课 - 金融市场课程节选

That's such an interesting issue, that again, when we return to talk about sex differences we'll look at that in a little bit more detail to see if it's supported by the evidence.

这是个非常有趣的问题,等我们讲到两性差异的时候,我们再来详细的讨论,是否有证据支持了该理论

耶鲁公开课 - 心理学导论课程节选

It says, well I'm going to print out first and last just so you can see it, and then I say, gee 2 if last minus first is less than 2, that is, if there's no more than two elements left in the list, then I can just check those two elements and return the answer.

然后它计算了尾点和开始点的差,如果小于2的话,也就是说数组中的元素小于等于，我对这两个元素进行比较,然后返回结果就可以了，否则的话，我们就去寻找中值点，注意它是怎么实现的,首先这个指向一个列表的开头。

麻省理工公开课 - 计算机科学及编程导论课程节选

The equally-weighted case that I gave a minute ago was one where the two assets had--were at the same-- had the same expected return and the same variance; but this is quite a bit more general.

我刚刚举的相同权重的例子,表示两种资产-,有相同的预期收益和相同的方差;,但这种情况更加普遍一些。

耶鲁公开课 - 金融市场课程节选

b times. So I've got to go 3 b steps. All right I've got to go through the loop b times I've got three steps each time, and then when I pop out of the loop, I've got two more steps. All right I've got the initiation of answer and the return of it.

好，我一共执行了b次循环,每次循环内部进行了三次基本操作,当跳出循环后还有两个基本操作，因此这个初始的答案就是,2+3b次基本操作,来完成这个循环。

麻省理工公开课 - 计算机科学及编程导论课程节选