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So Alpha does better. But if my pair chooses Beta, then Alpha gets me -1; Beta gets me 1.
此时选α较好,但是如果我对手选β,我选α得-1,选β得1
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I'm averaging it over the entire set of valence electrons which gives me 1.91 MJ per mole.
我是在整个价电子的集合上作平均,最后得到1。91兆焦每摩尔。
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But please try and look at--somebody's not looking at it, because they're using it as a fan here-- So look at Game 1 and fill out that form for me, okay?
请大家看下游戏1 我知道有人没看,他们用那张纸扇风呢,快浏览下游戏1 然后填完 好吗
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It costs me 1/.
我要花1/英镑
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6 Well again, we can go to our ones column, twos, four, eight, 16, 2 damn, 32. So we can go to 32 128 and then we can go to 64, and then 128, 1 2 3 4 5 6 7 8 and this gives me 1, 2, 3, 4, 5, 6, 7, 8.
好吧，再一次回到一位，二位，四位，八位，该死的，32，等等，所以我们可以找到32位2,再64，然后，那么我们就有了。
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Remember what range does, it gives me a set or a collection or a tuple of integers from 0 up to 1 - is the last value, so it's going to give me everything from 0 up to the total number of heads.
我将要在这个循环范围内加上鸡的数量,记住循环范围的目的,它给了我一个从一开始的整数集合,或者数组,这是最后的值。
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He greets his former rival and enemy with these words 1 This is in Genesis 33:10-11 If you would do me this favor, accept for me this gift, for to see your face is like seeing the face of God, And you have received me favorably.
他用以下的话来迎接往昔的仇敌,这段话出现在《创世纪》10章第10到11节中1,不然，我若在你眼前蒙恩，就求你从我手里收下这礼物，因为我见了你的面，如同见了神的面，并且你接纳了我。
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Let's take a system. Under constant pressure T1 V1, going to a second -- this is the system, so let me write the system here.
我们建立一个系统1,在恒定的压强T1，V1，下，变成了另一个系统，-这个初始的系统让我把它写在这。
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So if I produce one unit it costs me c; if I produce two units it costs me 2c; if I produce 100 units, it'll cost me 100c and if I produce 0.735 units that costs me 0.735c.
生产1单位的产品成本是c,如果生产2单位成本就是2c,如果我生产100单位成本就是100c,如果生产0.735单位就是0.735c
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And frankly it would be incredibly time-consuming and tedious for me, to count this room full of people old school style-- 1, 2, 3 and so forth.
坦白说，按学校的老办法一个人一个人的数,1个，2个，3个……,对我来说极其费时费力。
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Let me generalize this. In this case, my incrementer was just adding 1 to an integer, it's a pretty straightforward thing to do.
当我完成后，我不会再显示任何信息了，好，好，那么你们已经看过两个简单的例子了，让我来讲讲概念，在这个例子中。
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*10^-18 1.6 times 10 to the minus 18, excuse me, 6*10^-19 we have 1.6 times 10 to the minus 19, 2.18 times 10 to the minus 18, etc.
。,1。,2。18*10^-18，等等。
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For example, I may have someone who promises to pay me $1 in one year or in two years or three years.
举个例子,有人对我承诺,在一年或者两年或者三年内支付我一美元
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Let me divide this into 2 lists of size 1 and now done, right?
那么我将其划分为只有1个元素的2个列表？
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It means that choosing position 2 always gives me a higher share of the vote than choosing position 1, no matter where the other candidate positions herself.
意味着选择立场2,会比选择立场1,获得更多的选票,无论另一个候选人如何选择
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But you'll see that very clearly that Steven's right: that choosing 2 will always get me 5% more of the votes than choosing 1 from here on down.
你会发现斯蒂文说的很对,从这里开始,选立场2总会比,选立场1多获得5%选票
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What is Player 1's best response? Someone read it off for me.
谁来说一下,参与人1最佳对策是什么
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So this first little piece of code right here says, ok you give me 2 points, I'll create another 1 of these lists and I'll simply take the x, sorry I shouldn't say x, I'm going to assume it's the x, the x-values are the two points, add them together, just right there, the y-values, add them together and return that list.
好，为了来认识到这一点,让我们来看一个简单的小例子，在你们的课堂手册上，你可以看到我写了一个小程序,它假设我得到了，这些点中的一些，我想对它们做一些操作，例如我想把它们加到一起，那么这里的第一小片，代码的意思是，好给我两个点，我会再创建一个数组。
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If you want to get some input from the user, my God I don't want to have to program it to low level zero and 1 just to get keys from the keyboard; please let there have been someone who does that for me and indeed there are an increasingly sophisticated options that you can pull off the shelf.
如果你想获得一些用户的输入数据，我的上帝,我可不希望在键盘上敲入0，1的低水平方式来编程;,希望有个人能帮我做这件事吧,但是现有的选择,也变得日益复杂了。
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Exactly, so ignoring these first two positions which were a bit weird, choosing 2 always gave me 5% more votes than choosing 1, regardless of what the other person chooses.
完全正确,所以忽略前两个立场,因为前两个立场有点古怪,我们选立场2总比1多获得5%的选票,无论对手如何选择
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So where is--suppose he's pricing-- We'll say the prices are between 0 and 1, suppose he's pricing at .8, what would be a good price for me to set?
如果他定价,假设他的价格,取值在0和1之间,假设他的价格设定在0.8,我应该设定哪个价格比较好呢
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Let's just... We'll get there, just to remind you, the way we read this is you give me a quantity of Firm 2, I find Firm 1's best response by going across to the pink line and dropping down.
我们当然也能算出来,提醒一下各位,这个图像的个意思是任意给出公司2产量,然后通过这条粉色的线,就可找出与之对应的公司1的最佳对策
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I should have done this earlier by typing the Cartesian form earlier, so let me go back to where I was, sorry for that, let me go make this a 1 again.
我应该早点通过输入笛卡尔形式,来说明这个的，那么让我回到刚才说到的地方，很抱歉，让我去把，这个a，1再做一遍。
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I going to come back in a second to how it actually does that, but it basically says, get me x value for p 1, get me the x value for p 2, compare them, just as you would normally.
是一个类的实例,我要去取的这个实例，所关联的x值，我稍后会讲讲实际上，这里是怎么实现的，但是基本上它的意思就是，给我p1的x值。
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It tells me that the best response to S2 is the ?1 that solves this equation, that solves this first order condition.
我们得出S2的最佳对策是?1,?1是这个方程的解,它满足一阶条件
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Remember last time, we wrote this simple piece of code to print out even or odd. If, you know, x, 1 it was in fact, even or odd. So let me show you what a flow chart for that would look like, because I want to make a comparison point here.
这就像这里有一些脚蹼一样,首先进行测试，然后把球这样放来让ANS加,然后回来继续测试，最终跳出循环然后打印答案。
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same point It says, if you give me two of these data objects, I'm going to call them p 1 and p 2.
的代码，What，does，it，say，to，do？,你可以看看它,它是用来做什么的呢？,它的意思是，如果你给我两个。
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The way we read this green graph is you give me a choice of Firm 1, q1.
这条绿色的线表示,任意给出公司1的产量q1
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What's that telling me is that if Player 2 chooses not to produce then Player 1's best response is a - c over 2b.
参与人2产量为0而参与人1最佳对策是,/2b,这能说明什么
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