So the maximum work out required the maximum heat in.

因此输出最大的功要求,有最大的热。

麻省理工公开课 - 热力学与动力学课程节选

Maximum work out is by reversible path.

可逆过程产生最大功。

麻省理工公开课 - 热力学与动力学课程节选

So I differentiated this object, this is my first derivative and I set it equal to 0 Now in a second I'm going to work with that, but I want to make sure i'm going to find a maximum and not a minimum, so how do I make sure I'm finding a maximum and not a minimum?

这样我就对它求出导数了,这是一阶导数,令它等于0,一会我们就要计算了,但我先确定一下是最大值还是最小值,我怎么确定是最大值还是最小值呢

耶鲁公开课 - 博弈论课程节选

And what you'll find is that the maximum work out is obtain for a reversible path.

对于各种可能的中间路径，我们将发现,做功做多的是可逆路径。

麻省理工公开课 - 热力学与动力学课程节选