Two moles of mag consume one mole of tickle, giving us one mole of Ti, and that's 515 moles of tickle consumed.

两摩尔的镁消耗一摩尔的四氯化钛，得到一摩尔钛，也就是说需要消耗掉515摩尔的四氯化钛。

麻省理工公开课 - 固态化学导论课程节选

So, if you go and read Phil Mag 669-1911, you'll see Rutherford's model as it's presented.

如果你去读读1911年哲学杂志的的669页，你将看到卢瑟福的模型就和这展示的一样。

麻省理工公开课 - 固态化学导论课程节选

OK, so let's say some young engineer is on the job the first day and says, OK, let's put in 200 kg of tickle, and let's put in about 25 kg of mag.

比如一些年轻的工程师,刚来上班时会说，投入200kg的四氯化钛，投入25kg的镁。

麻省理工公开课 - 固态化学导论课程节选

It's tickle. This is mag.

而是tickle，这是镁。

麻省理工公开课 - 固态化学导论课程节选