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So we could have five values of m sub l.
所以它可以取5个值。
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We already know our value of m.
我们已经知道ｍ的值。
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I'm assuming all the components are positive.
我现在已经假设所有值都是正的
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And I think in the polar one I said, if, what did I do there, I said, yeah, again if the x and y are greater than the other one, I'm going to return them to it.
然后我要返回一些值，我认为在极坐标的形式下我说过，如果，我在这里做了什么来着,我说过，对，再说一次，如果x和y坐标。
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And we know from over here that 2p has the possibility of three different m numbers.
从这里我们知道,2p可能有三个不同的m值。
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I put it in n. So here's where I'm pushing back.
我把它赋值给n，我把它放回这里。
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So, if we think of just an example, 2 we could say that 4 l equals 2, what would be our lowest value of m sub l?
举个例子，如果我们说l等于，那m小标l，最小值是多少？
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So the allowed values for m sub l 0 are going to be negative l, all the way up to 0, l and then up to positive l.
所以m小标l的可能值,是从负l，一直到，然后到正。
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Again, the reason for that is because the energy only depends on the n value here, it doesn't depend on l or on m.
因为，能量,只和n的值有关，与l和m的值无关。
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So, our next level up that we can go is going to be the n equals 2 energy level, but we also have an l and an m value, 0 so our lowest l is going to be a there.
所以下一个能量,是n等于2的能级，但我们还有l和m的值，所以我们最低的l等于。
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I'm binding a z to be some value, and then I'm going to run this.
我把z绑定到一个值上，然后运行下代码。
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If I'm not going to take it I give it a 0.
我会给x赋值,如果我不打算带走。
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If you go and work that out, log2 log of two and you have two log two, by math you can show that for the line r series m 2*log2 is equal to two natural log of two, which is 1 1.386 which is greater than one.
如果你把它计算出来，这二者的对数，你会得到2个，通过数学，你会得到第r列，第m个值,等于,也就是1。386，这大于。
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That is seven different m values.
也就是说m有七个不同的值。
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I then assign thankful true, if so, but notice this little trick: -- I'm going to keep doing this while I am bang thankful -- bang exclamation point means "not," so this is shorthand, sort of clever elegant notation for "while I'm not thankful, keep doing this."
然后我给thankful赋true值，如果是这样，注意这里有个小技巧：,我将一直这样做，当我用满意时-,感叹号在这里的意思是“非“，这是一个可速记的，有几分机灵优雅的符号,用来说明：“当我不满意，保持这样做“
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