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RT2 So it's R T2, right, now we're at a lower temperature times log the log of V4 over V3.
等于，这时温度比刚才低,乘以。
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The integral of one over a quantity is the natural log.
这种形式的积分结果,是自然对数。
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If you get them backwards, logr you will integrate one over r and will get log r.
如果你逆推的话，对1/r积分得到。
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And so, we can rewrite this as the work nRTln is equal to minus nRT log p1 over p2, nRTln or nRT log p2 over p1.
因此我们可以把这个式子改写一下,功等于负的，或者。
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log So that's just the log of V2 over V1.
因此就是。
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And so we can write this, ln minus nRT log V2 over V1.
所以结果是，负的nRT除以。
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Wrev So minus w reversible, 1 p2 is less than p1, so p2 over p1 is less than one, log of something less than 1 is negative times negative.
那么，而p2小于p1，p2/p1小于，取对数后是负数,负负得正。
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w This is just q plus w. There's w, RT1 ln q has to be R T1 log of V2 over V1.
而U等于q加，那是w，q应该是。
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It's nR log of p2 over p1 for the process where there's a pressure change.
结果是dS等于nR乘以p2除以p1的对数,这是对压强变化的结果。
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So it's nR log V2 over V1.
结果是nR乘以V2除以V1的对数。
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We found that it's R log V2 over V1.
这是路径A，我们已经得到它。
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